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Alex17521 [72]
3 years ago
13

The volume of a gas is 200mL at 2.0atm. What will it's volume be at 4.0atm?​

Chemistry
2 answers:
Mnenie [13.5K]3 years ago
7 0

The new pressure will be

1000 L

, rounded to one significant figure.

Explanation:

Boyle's law states that when a gas is held at a constant temperature and mass in a closed container, the volume and pressure vary inversely. The equation to use is

P

1

V

1

=

P

2

V

2

.

Given

V

1

=

200

mL

×

1

L

1000

mL

=

0.2 L

P

1

=

700 mmHg

V

2

=

100

mL

×

1

L

1000

mL

=

0.1 L

Unknown

P

2

Equation

P

1

V

1

=

P

2

V

2

Solution

Rearrange the equation to isolate

P

2

and solve.

P

2

=

P

1

V

1

V

2

P

2

=

(

700

mmHg

×

0.2

L

)

0.1

L

=

1400 L

, which must be rounded to

1000 L

because all of the measurements have only one significant figure

BartSMP [9]3 years ago
4 0

Answer:

V = 100 ml

Explanation:

P1V1 = P2V2

P1 = 2.0 atm

V1 = 200ml

P2 = 4.0 atm

V2 = ?

(2.0)(200) = (4.0)V2

400 = (4.0)V2

V2 = 100

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Rufina [12.5K]
Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
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3 years ago
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ruslelena [56]

Answer:

O2, oxygen.

Explanation:

Hello.

In this case, for the undergoing chemical reaction, we need to compute the moles of CO2 yielded by 85 g of CH4 (molar mass = 16 g/mol) and by 320 g of O2 (molar mass 32 g/mol) via the following mole-mass relationships:

n_{CO_2}^{by\ CH_4}=85gCH_4*\frac{1molCH_4}{16gCH_4} *\frac{1molCO_2}{1molCH_4} =5.3molCO_2\\\\n_{CO_2}^{by\ O_2}=320gO_2*\frac{1molO_2}{32gO_2} *\frac{1molCO_2}{2molO_2} =5molCO_2

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Answer:

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Explanation:

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3 0
3 years ago
using the symbol M for the element, write the chemical formula for the compound that forms when element M reacts with iodine.
Anon25 [30]

Answer : The chemical formula for the compound is, MI

Explanation :

When the element 'M' react with the I_2 to give MI.

The balanced chemical reaction is,

2M+I_2\rightarrow 2MI

In this reaction, 'M' is in mono-atomic form and I_2 is in diatomic form.

By the stoichiometry,

2 moles 'M' react with the 1 mole of I_2 to give 2 moles of MI.

Therefore, the chemical formula of the compound is, MI


6 0
4 years ago
Read 2 more answers
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