Answer:
d(t) = -20t -260
Step-by-step explanation:
We are given two points ...
(t, d) = (3, -320) and (8, -420)
The 2-point form of the equation of a line can be useful when 2 points are given.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
Substituting the given points, we have ...
d(t) = (-420 -(-320))/(8 -3)(t -3) -320
d(t) = -20(t -3) -320
d(t) = -20t -260
Answer:
f x y z 4y cos (< x >) y x sin z z xy k s is the hemisphere x2 y2 z2 25 z ≥ 0 oriented upward
use stokes theorem to evaluate f dr
s is the hemisphere x 2 y 2 z 2 16
consists of the top and the four sides but not the bottom of the cube with vertices oriented outward
stokes theorem triangle with vertices
f xyz x y 2 i y z 2 j z x 2 k where k is the triangle with vertices
∫ f ∙ dr c when f x y z 2xi 3zj xk and c is the triangle with vertices 0 0 0 1 1 1 and 0 0 2
s is the part of the paraboloid z 1 − x2 − y2 that lies above the xy plane oriented upward
<span>The answers to this problem are:<span>(<span>±5</span></span>√3/8,±5/8)<span>Here is the solution:
Step 1: <span><span><span>x2</span>+<span>y2</span>=<span>2516</span>[2]</span><span><span>x2</span>+<span>y2</span>=<span>2516</span>[2]</span></span>
Step 2: Substitute:<span>
</span><span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)
</span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)</span></span>
</span><span>x^2</span>−<span>y^2</span>=<span>25/32</span><span>.
Add [2] and [3]:<span>
</span><span>2<span>x^2</span>=<span>75/32
</span><span>x^2</span>=<span>75/74</span></span>
<span>x=±5</span></span>√3/8<span>
Substitute into [2]:<span>
</span><span><span>75/64</span>+<span>y^2</span>=<span>50/32
</span><span>y^2</span>=<span>25/64</span></span>
<span>y=±<span>5/8</span></span>
</span>
</span>
