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Vlad1618 [11]
3 years ago
15

How can the rate of a reaction be increased?

Physics
2 answers:
Anni [7]3 years ago
6 0

Explanation:

There are many factors that are responsible for increasing the rate of reaction.

(1) Temperature: If the temperature increases, the kinetic energy of the molecules also increases. Hence, the collisions and ultimately the rate of reaction increases.

(2) The concentration of reactants: Higher the concentration, more will be the collision and hence more will be the rate of reaction.

(3) Pressure: Pressure is also directly proportional to the rate of reaction.

(4) Catalyst: Adding a catalyst increase the rate of reaction. Because it decreases the activation energy of the reactants. Hence, a small amount of energy is required by the reactants.

Hence, the above factors increases the rate of reaction.  

olya-2409 [2.1K]3 years ago
5 0
<h3><u>Answer and explanation;</u></h3>

-Rate of reaction is the speed at which the reactants are converted to products.

-Rate of reactions depends on a number of factors which includes<u>;</u>

  • <em><u>Concentration of reactants</u></em>;<u><em> increasing the concentration of reactants</em></u> increases the rate of reaction.
  • <u><em>Temperature;</em></u><u><em> </em></u>An <u><em>increase in temperature results to an increased rate of reaction.</em></u> Increase in temperature increases the kinetic energy of molecules thus the collision per unit time also increases and hence the rate of reaction increases.
  • <u><em>Decreasing the size of particles of solid reactants</em></u> also increases the rate of reaction. This is because smaller particles increases the surface area on which more collisions can occur thus a faster rate of reaction.
  • <em>Adding a catalyst also increases the rate of reaction.</em> This is because catalysts lower the activation energy of reactants, minimum energy require by reactants for the reaction to take place. This thus increases the rate of reaction.
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The speed of the ball moving is

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what is momentum?

The momentum p of a classical object of mass m and velocity v is given by pclassical =mv.

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h = 6.626 \times 10 {}^{ - 34}kgm {}^{2}/s(plancks \: constant)

λ = 700 \times 10 {}^{ - 9} m(photons \: wavelength)

p \: photons =  \frac{6.626 \times 10 {}^{ - 34}kgm {}  ^{2}/s }{700 \times 10 {}^{ - 9}m  }

= 9.47 \times 10 {}^{ - 28}kgm /s

since,the Photon and the ping-pong ball have the same momentum,we have

pball = pphotons =  \frac{6.626 \times 10 {}^{ - 34}kgm/s  }{700 \times 10 {}^{ - 9} }

pball = mv,m = 2.40 \times 10 {}^{ - 3}kg

v = 3.94 \times 10 {}^{ - 25} m/s

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v = 3.94 \times 10 {}^{ - 25}m/s

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