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Vlad1618 [11]
3 years ago
15

How can the rate of a reaction be increased?

Physics
2 answers:
Anni [7]3 years ago
6 0

Explanation:

There are many factors that are responsible for increasing the rate of reaction.

(1) Temperature: If the temperature increases, the kinetic energy of the molecules also increases. Hence, the collisions and ultimately the rate of reaction increases.

(2) The concentration of reactants: Higher the concentration, more will be the collision and hence more will be the rate of reaction.

(3) Pressure: Pressure is also directly proportional to the rate of reaction.

(4) Catalyst: Adding a catalyst increase the rate of reaction. Because it decreases the activation energy of the reactants. Hence, a small amount of energy is required by the reactants.

Hence, the above factors increases the rate of reaction.  

olya-2409 [2.1K]3 years ago
5 0
<h3><u>Answer and explanation;</u></h3>

-Rate of reaction is the speed at which the reactants are converted to products.

-Rate of reactions depends on a number of factors which includes<u>;</u>

  • <em><u>Concentration of reactants</u></em>;<u><em> increasing the concentration of reactants</em></u> increases the rate of reaction.
  • <u><em>Temperature;</em></u><u><em> </em></u>An <u><em>increase in temperature results to an increased rate of reaction.</em></u> Increase in temperature increases the kinetic energy of molecules thus the collision per unit time also increases and hence the rate of reaction increases.
  • <u><em>Decreasing the size of particles of solid reactants</em></u> also increases the rate of reaction. This is because smaller particles increases the surface area on which more collisions can occur thus a faster rate of reaction.
  • <em>Adding a catalyst also increases the rate of reaction.</em> This is because catalysts lower the activation energy of reactants, minimum energy require by reactants for the reaction to take place. This thus increases the rate of reaction.
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umka2103 [35]

Answer:

B = 0.024T positive z-direction

Explanation:

In this case you consider that the direction of the motion of the electron, and the direction of the magnetic field are perpendicular.

The magnitude of the magnetic force exerted on the electron is given by the following formula:

F=qvB     (1)

q: charge of the electron = 1.6*10^-19 C

v: speed of the electron = 1.6*10^7 m/s

B: magnitude of the magnetic field = ?

By the Newton second law you also have that the magnetic force is equal to:

F=qvB=ma       (2)

m: mass of the electron = 9.1*10^-31 kg

a: acceleration of the electron = 7.0*10^16 m/s^2

You solve for B from the equation (2):

B=\frac{ma}{qv}\\\\B=\frac{(9.1*10^{-31}kg)(7.0*10^{16}m/s^2)}{(1.6*10^{-19}C)(1.6*10^7m/s)}\\\\B=0.024T

The direction of the magnetic field is found by using the right hand rule.

The electron moves upward (+^j). To obtain a magnetic forces points to the positive x-direction (+^i), the direction of the magnetic field has to be to the positive z-direction (^k). In fact, you have:

-^j X ^i = ^k

Where the minus sign of the ^j is because of the negative charge of the electron.

Then, the magnitude of the magnetic field is 0.024T and its direction is in the positive z-direction

8 0
2 years ago
When a star is in the main-sequence stage of its life, it is fusing __________ into ________
gizmo_the_mogwai [7]
Hydrogen into helium
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2 years ago
A control clinic offers a program that guarantees a weight loss of up to 0.46 kg in one week. Express the weight loss in a ratio
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Answer:

0.76 mg/s

Explanation:

0.46 kg/week × (1 week / 7 days) × (1 day / 24 hrs) × (1 hr / 3600 s) × (1000 g/kg) × (1000 mg/g) = 0.76 mg/s

4 0
3 years ago
If the rest energies of a positive sigma particle and a lambda particle are 1189.4 and 1115.7 Mev respectively, what is the diff
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Answer:

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73.7 MeV = 73.7×1.6×10⁻¹⁹ J = 117.92×10⁻¹⁹ J

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From Einstein's equation

E = mc²

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8 0
2 years ago
Calculate the radius of curvatuire of the concave lens based on the measured focal length.
Roman55 [17]

Answer:

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where f is the focal length, n₂ is the refractive index of the material, n₀ is the refractive index of the medium surrounding the material, R₁ and R₂ are the radius of curvature of each of the material's

In our case, the most common is that the lens is in the air, so n1 = 1, in many cases one of the surfaces is flat, so its radius of curvature R₂ = ∞.

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we look for the radius of curvature R₁

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With this expression we can find the radius of curvature of a concave-plane lens

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