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3 years ago

what is the volume of the hamsta snack box with a width of 1 1/2 inches, a length of2 1/2 inches, and a height of 4 inches

Mathematics

1 answer:

jenyasd209 [6]3 years ago

3 0

<u>Given:</u>

The width of the snack box is $1 \frac{1}{2} \ inches=\frac{3}{2} \ inches$

The length of the snack box is $2 \frac{1}{2} \ inches=\frac{5}{2} \ inches$

The height of the snack box is 4 inches.

We need to determine the volume of the hamsta snack box.

<u>Volume of the box:</u>

The volume of the box can be determined using the formula,

$V=L \times W \times H$

where L is the length, W is the width and H is the height of the box.

Substituting the values, we get;

$V=4 \times \frac{3}{2} \times \frac{5}{2}$

Simplifying, we get,

$V=\frac{60}{4}$

$V=15 \ in^3$

Thus, the volume of the Hamsta snack box is 15 cubic inches.

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Step-by-step explanation:

Do Rachel and Dylan argree?

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Prove your answer using the values of the ratio.

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The ratio can be simplifies further by diving all through by 25;

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3 years ago

A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.

Verdich [7]

Answer:

$2a - 3b + 4c = 1$

Step-by-step explanation:

Given

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Required

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$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Open bracket

$a^2 + b^2 + c^2 = 2a - 2b - 2c - 3$

Equate the equation to 0

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0$

Express 3 as 1 + 1 + 1

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0$

Collect like terms

$a^2 - 2a + 1 + b^2 + 2b + 1 + c^2 + 2c + 1 = 0$

Group each terms

$(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

Factorize (starting with the first bracket)

$(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

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$((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + b+b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)(b + 1)) + (c^2 + 2c + 1) = 0$

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$((a - 1)^2) + ((b + 1)^2) + (c(c + 1)+1(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)(c + 1)) = 0$

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$(a - 1)^2 + (b + 1)^2 + (c + 1)^2 = 0 + 0+ 0$

By comparison

$(a - 1)^2 = 0$

$(b + 1)^2 = 0$

$(c + 1)^2 = 0$

Solving for $(a - 1)^2 = 0$

Take square root of both sides

$a - 1 = 0$

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$a - 1 + 1 = 0 + 1$

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4 years ago

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4 years ago

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emmainna [20.7K]

Let $x$ be the number of boxes the team brings with them. Their weight combined with the boxes can't exceed the capacity of 1400. Assuming the elevator runs fine at that exact weight, you want to find the number of boxes, each of which contributes 40 pounds. This is given by the equation

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Solving for $x$ , you have

$1400=1200-40x$
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4 years ago

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prohojiy [21]

Answer:

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Step-by-step explanation:

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3 years ago