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Scorpion4ik [409]
2 years ago
5

Darwin borrows $3,000 at an

Mathematics
1 answer:
aksik [14]2 years ago
3 0

Answer:

Interest = $600

Step-by-step explanation:

Interest = principal x rate as decimal x time

Interest = 3,000 x 0.04 x 5

Interest = 600

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If we buy 20 pickles what is the experimental probability of winning 5 or more tickets
Mrac [35]

Answer:

Pr = 0.66

Step-by-step explanation:

Given

See attachment for complete question

Required

P(x \ge 5)

From the attachment, we have:

S = 2 + 8 + 4+20+21+19+17+5+2+2

S =100 ---- the sample size

Next, we list out all outcomes more than or equal to 5.

i.e.

x \ge 5

5 is represented with the vertical blue rectangle (with frequency 21).

So, the other elements are to the right of frequency 21.

So, we have:

x \ge 5 = 21+19+17+5+2+2

x \ge 5 = 66

The probability is then calculated as:

Pr = \frac{x \ge 5}{S}

This gives

Pr = \frac{66}{100}

Pr = 0.66

8 0
3 years ago
Eat brainlyest cheese
umka2103 [35]

Answer:

fdiyshufsdhbdjfhsdfushdifusfhdifuhsd

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Jane will draw one card from the regular deck of 52 cards. In how many ways can she choose a jack or a black card?
elena-s [515]

Answer:

28

Step-by-step explanation:

In a regular 52 card deck, 26 are black (clubs or spades).  Additionally, there are two red jacks (diamonds and hearts).  This equals 28/52.  As a probability, it would be 28/52=14/26=7/13.  This could also be expressed as a percentage or decimal.  0.538 or 53.8%.  But the question asks <em>how many ways</em> can she choose a jack or black card, so I’m assuming they don’t want the probability, just the number, which is 28.

3 0
3 years ago
Read 2 more answers
How much water should be added to 14mL of 15% alcohol solution to reduce the concentration to 7%
leonid [27]
You would need 12ml of water.

6 0
3 years ago
The weight of Jane and Jessica was in the ratio of 8 : 9. Jane gained 2 kg while Jessica lost 4 kg. They then had the same weigh
postnew [5]

Answer:

  48 kg

Step-by-step explanation:

The given relations can be used to write a system of equations for the two weights. Those can be solved to find Jane's weight.

__

<h3>setup</h3>

Let x and y represent Jane's and Jessica's original weight, respectively. The ratio of weights was ...

  x/y = 8/9

After the changes in weight, they were equal:

  x+2 = y-4

__

<h3>solution</h3>

Adding 4 to the second equation, we have an expression for y that can be substituted into the first equation.

  y = x +6 . . . . . . . . . . solve the second equation for y

  x/(x+6) = 8/9 . . . . . . substitute for y in the first equation

  9x = 8(x +6) . . . . . . . multiply by 9(x+6)

  x = 48 . . . . . . . . . . . simplify and subtract 8x

Jane weighed 48 kg at first.

_____

<em>Alternate solution</em>

The original difference in "ratio units" was 9-8 = 1 ratio unit. We find that this corresponds to 6 kg after the weight changes make the weights equal. Then 8 ratio units will be 8(6 kg) = 48 kg—Jane's original weight.

(This mental solution is virtually the same as the solution using equations shown above.)

3 0
1 year ago
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