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WINSTONCH [101]

3 years ago

6

Question 2 help me and i'll give u brainlest

1 answer:

satela [25.4K]3 years ago

6 0

Answer:

respiratory

Explanation:

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A ball is thrown straight up into the air. At each of the following instants, is the ball's acceleration ay equal to g, −g, 0, g

Leto [7]

Answer:

a= (-g) from the moment the ball is thrown, until it stops in the air.

a = (0) when the ball stops in the air.

a = (g) since the ball starts to fall.

Explanation:

The acceleration is <em>(-g)</em> <em>from the moment the ball is thrown, until it stops in the air</em> because the movement goes in the opposite direction to the force of gravity. In the instant <em>when the ball stops in the air the acceleration is </em><em>(0)</em> because it temporarily stops moving. Then, <em>since the ball starts to fall, the acceleration is </em><em>(g)</em><em> </em>because the movement goes in the same direction of the force of gravity

6 0

3 years ago

Read 2 more answers

A hockey puck sliding at 60.0m/s slows uniformly to 20.0m/s while travelling 800.0m.

julia-pushkina [17]

A) -3.75 meters/second
A=(20^2-80^2)/(2x800)
=(400-6400)/1600
=-6000/1600
=-3.75
B) 16 seconds
t=(20-80)/-3.75
=-60/-3.75
=16

3 0

3 years ago

A sound wave has a speed of

ELEN [110]

Explanation:

use the formula

speed = frequency x wavelength

330 = frequency x 0.372

330 / 0.372 = frequency

887 Hz = frequency

hope this helps, please mark it brainliest

7 0

3 years ago

What’s happening to the car’s motion?

ExtremeBDS [4]

Answer:

It returned to where it had started at the end of the trip

Explanation:

5 0

3 years ago

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The magnetic field inside a 5.0-cm-diameter solenoid is 2.0 T and decreasing at 5.00 T/s. Part A) What is the electric field str

Veronika [31]

Answer:

(A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is $3.75\times10^{-2}\ V/m$ .

Explanation:

Given that,

Magnetic field = 2.0 T

Diameter = 5.0 cm

Rate of decreasing in magnetic field = 5.00 T/s

(A). We need to calculate the electric field strength inside the solenoid at a point on the axis

Using formula of electric field inside the solenoid

$E=\dfrac{r}{2}|\dfrac{dB}{dt}|$

Electric field on the axis of the solenoid

Here, r = 0

$E=\dfrac{0}{2}\times5.00$

$E = 0$

The electric field strength inside the solenoid at a point on the axis is zero.

(B). We need to calculate the electric field strength inside the solenoid at a point 1.50 cm from the axis

Using formula of electric field inside the solenoid

$E=\dfrac{r}{2}|\dfrac{dB}{dt}|$

$E=\dfrac{1.50\times10^{-2}}{2}\times|5.00|$

$E=0.0375= 3.75\times10^{-2}\ V/m$

Hence, (A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is $3.75\times10^{-2}\ V/m$ .

4 0

4 years ago