Answer:
3 Cr²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Cr₃(PO₄)₂(s)
Explanation:
When aqueous solutions of chromium(II) iodide and sodium phosphate are combined, solid chromium(II) phosphate and a solution of sodium iodide are formed. The molecular equation is:
3 CrI₂(aq) + 2 Na₃PO₄(aq) ⇄ Cr₃(PO₄)₂(s) + 6 NaI(aq)
The full ionic equation includes all the ions and the molecular species.
3 Cr²⁺(aq) + 6 I⁻(aq) + 6 Na⁺(aq) + 2 PO₄³⁻(aq) ⇄ Cr₃(PO₄)₂(s) + 6 Na⁺(aq) + 6 I⁻(aq)
The net ionic equation includes only the ions that participate in the reaction and the molecular species.
3 Cr²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Cr₃(PO₄)₂(s)
Answer:
We're asked to find the molar concentration of the
NaCl
solution given some titration data.
Let's first write the chemical equation for this reaction:
NaOH
(
a
q
)
+
HCl
(
a
q
)
→
NaCl
(
a
q
)
+
H
2
O
(
l
)
Using the molarity equation, we can find the number of moles of
HCl
that reacted:
molarity
=
mol solute
L soln
mol solute
=
(
molarity
)
(
L soln
)
mol HCl
=
(
0.105
mol
L
)
(
0.0250
L
)
=
0.00263
mol HCl
(volume converted to liters)
Now, using the coefficients of the chemical reaction, we can determine the number of moles of
NaOH
that reacted:
0.00263
mol HCl
(
1
l
mol NaOH
1
mol HCl
)
=
0.00263
mol NaOH
Lastly, we'll use the molarity equation (using given volume of
NaOH soln
) again to determine the molarity of the sodium hydroxide solution:
molarity
=
mol solute
L soln
M
NaOH
=
0.00263
l
mol
0.315
l
L
=
0.00833
M
(volume converted to liters)
Radiation is s very powerful substance and can cause major health problems do the health care professionals limit the use to help not create sickness
Answer:
In case of low-mass stars,the outer layers of the low mass stars are expelled as the core collapses such that the outer layers form a planetary nebula.
Explanation:
In case of low-mass stars,the outer layers of the low mass stars are expelled as the core collapses such that the outer layers form a planetary nebula. The core remains as a white dwarf and finally become a black dwarf as it cools down. A low mass star consumes its core hydrogen and turns it into helium over its lifetime.
