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Tpy6a [65]
4 years ago
6

A severe thunderstorm dumped 2.0 in of rain in 30 min on a town of area 22 km2. what mass of water fell on the town? one cubic m

eter of water has a mass of 103 kg.
Physics
2 answers:
AlekseyPX4 years ago
7 0
For this case, the first thing you should know is that density is defined as the quotient between mass and volume.
 d = m / v
 We have then for this case that the density is:
 d = 103 Kg / m ^ 3
 The volume is given by:
 V = A * d
 Where
 A: area of the city
 d: height of the rain
 Also, for calculation purposes, you must know the following measure:
 1Km = 1000m
 1 inch = 0.0254 meters
 Calculating the volume we have:
 V = (22 * (1000/1) ^ 2) * (2 * (0.0254 / 1)) = 1117600 m ^ 3
 Then, calculating the mass we have:
 m = d * v
 m = (103) * (1117600) = 115112800 Kg
 Equivalently
 m = 1.15 * 10 ^ 8 Kg
 answer
 mass of water fell on the town was 1.15 * 10 ^ 8 Kg
Naily [24]4 years ago
5 0
We want to convert everything to meters so we can calculate cubic meter volume and use the given mass information.  
2 inches = 5.08 centimeters = .0508 meters.  
22 square kilometers = 22,000,000 sq meters.  
The product of these gives the number of cubic meters of water that rained. .0508 * 22,000,000 = 1,117,600 cubic meters.  
Multiply by the mass to arrive at final answer. 1,117,600 m^3 * 103kg/m^3 = 115,112,800 kg  
115,112,800 kg of water fell.
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Hence, according to the subtractive theory, if we join the three primary colors of the pigments, we will obtain the black. Unlike the additive theory of light, in which if we join the three primary colors we will get white light.

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vichka [17]

Answer:

1.) 0 kgm/s

2) 6.3 kg

3) -0.0978 m/s

4)

5)

6)

An object with total mass mtotal = 16.2 kg is sitting at rest when it explodes into three pieces. One piece with mass m1 = 4.7 kg moves up and to the left at an angle of θ1 = 23° above the –x axis with a speed of v1 = 25.4 m/s. A second piece with mass m2 = 5.2 kg moves down and to the right an angle of θ2 = 28° to the right of the -y axis at a speed of v2 = 23.8 m/s.

2) What is the mass of the third piece?

3) What is the x-component of the velocity of the third piece?

4) What is the y-component of the velocity of the third piece?

5) What is the magnitude of the velocity of the center of mass of the pieces after the collision?

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Explanation:

Since explosions and collisions follow the law of conservation of Momentum.

1) Magnitude of the final momentum of the system = Magnitude of the initial momentum of the system

Since the body was initially at rest,

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