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<span>KE = 1/2mv^2 = (1/2)(2000)(2^2) = 4000 J This must equal the net work acting on the car. W=Fd The net force is 1140-950= 190N. so, d=W/F = 4000/190 = 21.05 m</span>
The increase in temperature of the metal hammer is 0.028 ⁰C.
The given parameters:
- <em>mass of the metal hammer, m = 1.0 kg</em>
- <em>speed of the hammer, v = 5.0 m/s</em>
- <em>specific heat capacity of iron, 450 J/kg⁰C</em>
The increase in temperature of the metal hammer is calculated as follows;

where;
<em>c is the </em><em>specific heat capacity</em><em> of the metal hammer</em>
<em />
Assuming the metal hammer is iron, c = 450 J/kg⁰C

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.
Learn more about heat capacity here: brainly.com/question/16559442
Answer:920.31 J
Explanation:
Given
Volume of water (V)
mass(m)
Temperature 
Final Temperature 
specific heat of water(c)
Therefore heat required to removed is



Answer:
<h2>5 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula

f is the force
m is the mass
We have

We have the final answer as
<h3>5 m/s²</h3>
Hope this helps you
(b) 71%
The thermal efficiency of a Carnot heat engine is given by:

where
W is the useful work done by the engine
is the heat in input to the machine
In this problem, we have:
is the heat absorbed
is the work done (175 kJ is the heat released to the sink, therefore the work done is equal to the difference between the heat in input and the heat released)
So, the efficiency is

(a) 
The efficiency of an engine can also be rewritten as

where
is the absolute temperature of the cold sink
is the temperature of the source
In this problem, the temperature of the sink is

So we can re-arrange the equation to find the temperature of the source:
