Answer:
6104 N/C.
Explanation:
Given:
k = 8.99 × 10^9 Nm2/C^2
Qx = 1.3 × 10^-5 C
rx = 7 m
Qy = 1 × 10−5 C
ry = 4 m
E = F/Q
= kQ/r^2
Ex = (8.99 × 10^9 × 1.3 × 10^−5) ÷ 7^2
= 2385.1 N/C.
Ey = (8.99 × 10^9 × 1.0 × 10^−5) ÷ 4^2
= 5618.75 N/C
Eo = sqrt(Ex^2 + Ey^2)
= sqrt(3.157 × 10^7 + 5.69 × 10^6)
= 6104 N/C.
Answer:
t = 3.35 s
Explanation:
It is given that,
Mass of a pumpkin, m = 8 kg
It is dropped from a height of 55 m
We need to find the time taken by it to hit the ground.
Initial velocity of the pumpkin, u = 0
Using second equation of motion to find it as follows :
So, it will take 3.35 seconds to hit the ground.
<h3>
Answer: D) 30</h3>
Angle of incidence always equals angle of reflection. Think of a tennis ball being hit into a wall. The ball will bounce off at the same angle that it approached with. The angles mentioned are formed through the line called the "normal", which is the line perpendicular to the surface.
Answer:
conserved
Explanation:
During this process the energy is conserved
Kinetic energy=1/2mv^2
=1/2(142*10^-3)(42.9)^2=130.6=131J
