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Naddika [18.5K]
2 years ago
11

Compare animal and plant cell

Physics
2 answers:
vagabundo [1.1K]2 years ago
8 0

Answer:

A plant cell contains a large, singular vacuole that is used for storage and maintaining the shape of the cell. In contrast, animal cells have many, smaller vacuoles. Plant cells have a cell wall, as well as a cell membrane. Animal cells simply have a cell membrane, but no cell wall.

hope this helps :)

natta225 [31]2 years ago
8 0

Answer:

Compare animal cell and plant cell: Both are eukaryotic cells, both contain membrane bound organelles. Both contain similar membranes such as cytosol and cytosketal elements.

Explanation:

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I need the science answer step by step
sukhopar [10]
What is the question
7 0
3 years ago
If we start with 48 g of a radioactive substance with a 2 hour 12 life, how much is left after two half-lives?
ivolga24 [154]

Explanation:

 Half-life is the time taken for a radioactive material to decay to half its original composition:

   Original mass = 48g

   Half- life  = 2hr

 

 After four half lives;

           Initially:                48g

    First halving                24

    Second halving          12

    Third halving               6

    Fourth halving             3

After second half life, we would have 12g

At fourth halving, we would have 3g

4 0
2 years ago
A spring hangs at rest from a support. If you suspend a 0.46 kg mass from the spring it elongates 0.79m.
Fudgin [204]

a. The restoring force in the spring has magnitude

F[spring] = k (0.79 m)

which counters the weight of the mass,

F[weight] = (0.46 kg) g = 4.508 N

so that by Newton's second law,

F[spring] - F[weight] = 0   ⇒   k = (4.508 N) / (0.79 m) ≈ 5.7 N/m

b. Using the same equation as before, we now have

F[weight] = (0.75 kg) g = 7.35 N

so that

(5.7 N/m) x - 7.35 N = 0   ⇒   x = (7.35 N) / (5.7 N/m) ≈ 1.3 m

4 0
2 years ago
Two people are standing on a 1.75-m-long platform, one at each end. The platform floats parallel to the ground on a cushion of a
Fiesta28 [93]

Answer:

0.05312 m

Explanation:

Given:

Length of platform L = 1.75 m

mass of ball m_b = 5.76 kg

mass of (people + platform) m_p = 184 kg

Initial Velocity of ball V_i,b = 0

Initial Velocity of ball (people + platform) V_i,p = 0

Find:

How far does the platform recoils to rest

Solution:

Using the conservation of momentum on ust before and after the ball was thrown P_i = P_f :

Where, P_i = 0 (initially at rest)

P_f = m_p*V_f,p + m_b * V_f,b

0 = m_p*V_f,p + m_b * V_f,b

V_f,p = - (m_b /m_p) * V_f,b

V_f,p = - (5.76 / 184)*V_f,b

V_f,p = - 0.0313*V_f,b   ....1

The time the ball is in air:

t = L / (V_f,b - V_f,p)   ...2

The distance that the platform moves d:

d = V_f,p *t  ....3

Substitute 2 into 3

d = V_f,p*L /(V_f,b - V_f,p)   .... 4

Solve 1 and 4 simultaneously :

d = - m_b*L / (m_b + m_p)

d = - 5.76*1.75 / (5.76 + 184)

d = -0.05312 m

The platform moves 0.05312 m to the opposite to which the ball is thrown.

5 0
3 years ago
I need help with my homework please? I will give a lot of points and a brainlist.
Sladkaya [172]

Answer:

1. False

some metals are ferromagnetic

2.True

3. True

4. True

5. False

The strength of electromagnetic can be increased by increasing the number of wire around it

4 0
2 years ago
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