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Naddika [18.5K]
2 years ago
11

Compare animal and plant cell

Physics
2 answers:
vagabundo [1.1K]2 years ago
8 0

Answer:

A plant cell contains a large, singular vacuole that is used for storage and maintaining the shape of the cell. In contrast, animal cells have many, smaller vacuoles. Plant cells have a cell wall, as well as a cell membrane. Animal cells simply have a cell membrane, but no cell wall.

hope this helps :)

natta225 [31]2 years ago
8 0

Answer:

Compare animal cell and plant cell: Both are eukaryotic cells, both contain membrane bound organelles. Both contain similar membranes such as cytosol and cytosketal elements.

Explanation:

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You've recently read about a chemical laser that generates a 20.0-cm-diameter, 26.0 MW laser beam. One day, after physics class,
aksik [14]

Answer :

(a). The speed of the block is 0.395 m/s.

(b). No

Explanation :

Given that,

Diameter = 20.0 cm

Power = 26.0 MW

Mass = 110 kg

diameter = 20.0 cm

Distance = 100 m

We need to calculate the pressure due to laser

Using formula of pressure

P_{r}=\dfrac{I}{c}

P_{r}=\dfrac{P}{Ac}Put the value into the formula[tex]P_{r}=\dfrac{26.0\times10^{6}}{\pi\times(10\times10^{-2})^2\times3\times10^{8}}

P_{r}=2.75\ N/m^2

We need to calculate the force

Using formula of force

F=P\times A

F=P\times \pi r^2

Put the value into the formula

F=2.75\times\pi (0.01)^2

F=0.086\ N

We need to calculate the acceleration

Using formula of force

F=ma

Put the value into the formula

0.086=110\times a

a=\dfrac{0.086}{110}

a=0.000781\ m/s^2

a=7.81\times10^{-4}\ m/s^2

(a). We need to calculate speed of the block

Using equation of motion

v^2=u^2+2ad

Put the value into the formula

v=\sqrt{2\times7.81\times10^{-4}\times100}

v=0.395\ m/s

(b). No because the velocity is very less.

Hence, (a). The speed of the block is 0.395 m/s.

(b). No

8 0
2 years ago
What two characteristics do electromagnetic waves vary in?
rosijanka [135]
They size of the wave and the time of a certain wave.
4 0
3 years ago
Read 2 more answers
Calculate the force of gravity on the 0.60- kg mass if it were 1.3×107 m above Earth's surface (that is, if it were three Earth
nignag [31]
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation

In this problem, the first object has a mass of m_1=0.60 kg, while the second "object" is the Earth, with mass m_2=5.97 \cdot 10^{24}kg. The distance of the object from the Earth's center is r=1.3 \cdot 10^7 m; if we substitute these numbers into the equation, we find the force of gravity exerted by the Earth on the mass of 0.60 kg:
F=G \frac{m_1m_2}{r^2}=(6.67\cdot 10^{-11}) \frac{(0.60 kg)(5.97 \cdot 10^{24} kg)}{(1.3 \cdot 10^7 m)^2}=  1.41 N
5 0
3 years ago
Please help! 100 points!
gregori [183]

Answer:

1.Nitrification happens when soil organisms change over ammonium into nitrate. Much of the cover between the carbon cycle and the nitrogen cycle happens within the soil, in forms conducted by soil organisms. Organisms break down supplements, construct modern compounds for their possess development, and inevitably pass on.

The second question im not sure sorry- the positive and negative one ;(

3. Many human activities have a significant impact on the nitrogen cycle. Burning fossil fuels, application of nitrogen-based fertilizers, and other activities can dramatically increase the amount of biologically available nitrogen in an ecosystem. As nitrogen makes up 78% of the atmosphere, there is no shortage of it – it just isn't in a form plants and animals can use.

4. Carbon makes its way through living things as carbon-based compounds, like vitality particles, fats and proteins, in the long run cycling its way back into the environment. Nitrogen is basically found within the air as well and enters the environments as supplements for plants. Water, nitrogen and carbon cycles. Carbon moves from the air and back by means of creatures and plants. Nitrogen moves from the environment and back by means of living beings. Water moves on, over, or underneath the surface of the Soil.

5. Carbon cycle, Nitrogen cycle, Nutrient cycle, Oxygen cycle, Phosphorus cycle, Sulfur cycle, Rock cycle, Water cycle.

6. Wind, water, and ice disintegrate and shape the arrive. Volcanic movement and seismic tremors change the scene in a sensational and frequently savage way. And on a much longer timescale, the development of earth's plates gradually reconfigures seas and landmasses. Each one of these forms plays a part within the Cold and Antarctica.

People affect the physical environment in numerous ways: overpopulation, contamination, burning fossil powers, and deforestation. Changes like these have activated climate alter, soil disintegration, destitute discuss quality, and undrinkable water. Earth's surface is the as it were territory accessible to the human race. Understanding the forms by which that environment has been made and persistently changed is critical to decide the causes of natural degradation.

3 0
2 years ago
A rectangular tank is filled to a depth of 10m with freshwater and open to air at atmospheric pressure.
charle [14.2K]

Answer:

<em>1.</em> <em>39068.07 N</em>

<em>2. 19534.036 N</em>

Explanation:

depth of water h = 10 m

atmospheric pressure Patm = 101325 Pa

density of water p = 1000 kg/m^3

acceleration due to gravity g = 9.81 m/s^2

pressure due to depth of water = pgh

P = 1000 x 9.81 x 10 = 98100 Pa

total pressure on the bottom of the tank is Patm + p = 101325 + 98100 = 199425 Pa

Left plug has diameter = 50 cm = 0.5 m

radius = 0.5/2 = 0.25 m

height = 1 cm = 0.01 m

<em>height below tank surface = 10 - 0.01 = 9.99</em>

pressure at this depth =  1000 x 9.81 x 9.99 = 98001.9 Pa

<em>total pressure = Patm + P = 101325 + 98001.9 = 199326.9 Pa</em>

surface area of plug = πr^{2} = 3.142 x 0.25^{2} = 0.196 m^{2}

<em>force required to lift left plug = pressure x area</em>

F =  199326.9 x 0.196 = <em>39068.07 N</em>

<em>The right side is a hemisphere with the same diameter, therefore surface area is half of the left plug</em>

A = 0.196/2 = 0.098 m^{2}

force F required to lift right plug =  199326.9  x 0.098 =<em> 19534.036 N</em>

6 0
3 years ago
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