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3 years ago

An apple drops from a tree and hits the ground in 1.5s what is its speed just before it hits the ground?

Physics

1 answer:

Zarrin [17]3 years ago

8 0

Vf - Vo = gT

where

Vf = velocity of apple just before hitting the ground

Vo = initial velocity of apple = 0

T = time for apple to hit the ground = 1.5 sec (given)

g = acceleration due to gravity = 9.8 m/sec^2 (constant)

Substituting appropriate values,

Vf - 0 = 9.8(1.5)

Vf = 14.7 m/sec.

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Answer:

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b) $F'=1.044\times 10^9\ N$

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d) Treat the humans as though they were points or uniform-density spheres.

Explanation:

Given:

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radius of the Mars, $r=3.4\times 10^{6}\ m$

mass of human, $m=80\ kg$

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where:

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$F=1.044\times 10^9\ N$

The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.

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$F'=1.044\times 10^9\ N$

When a similar person of the same mass is standing at a distance of 4 meters:

$F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}$

$F_p=1.0672\times10^{-7}\ N$

The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.

Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.

Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.

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