Answer:
<em>The drop voltage is 0.3 V</em>
Explanation:
Electromotive Force EMF
When connecting a battery of internal resistance Ri and EMF ε to an external resistance Re, the current through the circuit is:
![\displaystyle i=\frac{\varepsilon }{R_e+R_i}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20i%3D%5Cfrac%7B%5Cvarepsilon%20%7D%7BR_e%2BR_i%7D)
The battery has an internal resistance of Ro=2 Ω, ε=24 V and is connected to an external resistance of Re=158 Ω. Thus, the current is:
![\displaystyle i=\frac{24 }{158+2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20i%3D%5Cfrac%7B24%20%7D%7B158%2B2%7D)
![\displaystyle i=\frac{24 }{160}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20i%3D%5Cfrac%7B24%20%7D%7B160%7D)
i = 0.15 A
The drop voltage is the voltage of the internal resistance:
![V_i = i.R_i](https://tex.z-dn.net/?f=V_i%20%3D%20i.R_i)
![V_i = 0.15*2](https://tex.z-dn.net/?f=V_i%20%3D%200.15%2A2)
![\boxed{V_i = 0.3\ V}](https://tex.z-dn.net/?f=%5Cboxed%7BV_i%20%3D%200.3%5C%20V%7D)
The drop voltage is 0.3 V
Answer:
The Earth is toward the sun
Explanation:
DONT LISTEN TO ME I AM A CHILD AND I JUST GUESSED
The final velocity of the truck is found as 146.969 m/s.
Explanation:
As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.
Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.
![2as =v^{2} - u^{2} \\\\v^{2} = 2as + u^{2}](https://tex.z-dn.net/?f=2as%20%3Dv%5E%7B2%7D%20-%20u%5E%7B2%7D%20%5C%5C%5C%5Cv%5E%7B2%7D%20%3D%202as%20%2B%20u%5E%7B2%7D)
Then, the final velocity will be
![v^{2} = 2 * 3 * 3600 + 0 = 21600\\ \\v=\sqrt{21600}=146.969 m/s](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%202%20%2A%203%20%2A%203600%20%2B%200%20%3D%2021600%5C%5C%20%5C%5Cv%3D%5Csqrt%7B21600%7D%3D146.969%20m%2Fs)
Thus, the final velocity of the truck is found as 146.969 m/s.