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Yanka [14]
3 years ago
10

what is the efficiency of an engine that dies 288 J of work and exhausts 72 J of heat while taking 360 J of heat?

Physics
1 answer:
Yuliya22 [10]3 years ago
5 0

Answer:

80%

Explanation:

Energy Input: 360 J

Energy Output: 288 J

e= 288/360 × 100

e= 80%

Alternatively,

e= W(total)/ Q (in)

e= 288/360

e=0.8×100

e=80%

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The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

q=m\times c\times (T_2-T_1)

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = 4.18J/g.K

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T_2 = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

q=250g\times 4.18J/g.K\times (371.2-293.0)K

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\Delta H=\frac{q}{n}

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Now put all the given values in the above formula, we get:

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Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0
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