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vodomira [7]
3 years ago
15

What are two most important processes in the cycling of oxygen in and out of the atmosphere?

Physics
1 answer:
natulia [17]3 years ago
7 0
Weathering and erosion
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Part A<br>Does the number of particles change as the substance changes its state?​
vovangra [49]

No, the number of particles does not change as the substance changes its state.

<h3><u>Explanation: </u></h3>

Change of state from one phase to another is achieved by providing or absorbing heat or pressure. For instance, liquid water if heated becomes vapour steam and if cooled becomes solid ice. Vapour can be compressed to form liquid water again and thus change of state is a reversible action.

The "chemical composition of the matter remains the same" irrespective of its state. Unless a chemical change is carried out, no change occurs with the number of particles. Phase change only affects the "arrangement of molecules", its structure and its motion.

6 0
3 years ago
URGENT HELP! <br> How is it that two moving objects can have a net momentum of zero?
Zielflug [23.3K]

Answer:

because they may not actually be moving be just percieved as so

Explanation:

8 0
3 years ago
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In a car how does an air bag minimize the force acting on a person during a collision
Klio2033 [76]
It decreases the momentum in the car.
4 0
3 years ago
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If an oscillating mass has a frequency of 1.25 Hz, it makes 100 oscillations in
KatRina [158]

Answer:

Time, t = 80 seconds

Explanation:

Given that,

The frequency of the oscillating mass, f = 1.25 Hz

Number of oscillations, n = 100

We need to find the time in which it makes 100 oscillations. We know that the frequency of an object is number of oscillations per unit time. It is given by :

f=\dfrac{n}{t}

t=\dfrac{n}{f}

t=\dfrac{100}{1.25\ Hz}

t = 80 seconds

So, it will make 100 oscillations in 80 seconds. Hence, this is the required solution.

4 0
3 years ago
A sock stuck to the inside of the clothes dryer spins around the drum once every 2.0 s at a distance of 0.50 m from the center o
Rashid [163]

a) 1.57 m/s

The sock spins once every 2.0 seconds, so its period is

T = 2.0 s

Therefore, the angular velocity of the sock is

\omega=\frac{2\pi}{T}=\frac{2\pi}{2.0}=3.14 rad/s

The linear speed of the sock is given by

v=\omega r

where

\omega is the angular velocity

r = 0.50 m is the radius of the circular path of the sock

Substituting, we find:

v=(3.14)(0.50)=1.57 m/s

B) Faster

In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:

r' = 2r = 1.00 m

At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:

\omega' = \omega = 3.14 rad/s

Therefore, the new linear speed would be:

v'=\omega' r' = \omega (2r)

And substituting,

v'=(3.14)(1.00)=3.14 rad/s = 2v

So, we see that the linear speed has doubled.

8 0
3 years ago
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