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STALIN [3.7K]
3 years ago
11

You're using a wedge to split a log. you are hitting the wedge with a large hammer to drive it into the log. it takes a force of

1900 n to push the wedge into the wood. if the wedge moves 0.23 m into the log, how much work have you done on the wedge?
Physics
2 answers:
KIM [24]3 years ago
6 0
The work performed on an object is the force multiplied by the distance it is moved, provided the movement is parallel to the force.  Since that is the case here, we can get the work by W=Fd=1900N x 0.23m = 437J.  This energy is used to split the wood.
RoseWind [281]3 years ago
5 0

Answer: 437 J

Work done can be defined as the product of force and displacement. It is the work required to move an object to certain distance using a certain force.

work=force\times displacement

It is given that:

Force=1900 N

Displacement=0.23 m

Then, work=1900N\times 0.23m = 437 N-m=437J

Hence, the work done on the wedge to drive it into log is 437 J


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<u>Answer:</u> The Young's modulus for the wire is 6.378\times 10^{10}N/m^2

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Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}

where,

Y = Young's Modulus

F = force exerted by the weight  = m\times g

m = mass of the ball = 10 kg

g = acceleration due to gravity = 9.81m/s^2

l = length of wire  = 2.6 m

A = area of cross section  = \pi r^2

r = radius of the wire = \frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m      (Conversion factor:  1 m = 1000 mm)

\Delta l = change in length  = 1.99 mm = 1.99\times 10^{-3}m

Putting values in above equation, we get:

Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2

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4 years ago
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<u><em>Answer:Just as wavelength and frequency are related to light, they are also related to energy. The shorter the wavelengths and higher the frequency corresponds with greater energy. So the longer the wavelengths and lower the frequency results in lower energy.</em></u>

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A 38.2 kg wagon is towed up a hill inclined at 17.5 ◦ with respect to the horizontal. The tow rope is parallel to the incline an
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Answer:

v = 8.57 m/s

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Answer:

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