1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zaharov [31]
3 years ago
10

A student pushed a box 32.0 m across a smooth, horizontal floor using a constant force of 124 N. If the force was applied for 8.

00 s, how much power was developed, to the nearest watt?
Physics
2 answers:
Vika [28.1K]3 years ago
6 0
You need to calculate the work needed. This is force x distance in this case.
After you do that, divide the work by the time.
Brilliant_brown [7]3 years ago
3 0

The power developed is 500 W ( to the nearest Watt)

Power(P) is the rate at which work is done. Work done (W) is the product of the force applied on the object and the displacement (s) made by the point of application of the force.

P = \frac{W}{t}

W= F*s

Therefore,

P=\frac{F*s}{t}

Substitute the given values of force , displacement and time

F = 124 N,s = 32.0 m,t = 8.0 s

P =\frac{W*s}{t} =\frac{124N*22.0s}{8.0s} =496 W

Thus the Power can be rounded off to the nearest value of 500 W

You might be interested in
Which equipment would help you separate a liquid mixture by distillation?
anzhelika [568]
Distillation is a process in many laboratories for the purpose of separating and/or purifying components of a liquid mixture. The distillation apparatus used consists of three major parts: <span>distillation flask - to heat the mixture and volatilize the components, a condenser to cool the vapors back to liquid state, and a collection vessel.  The apparatus is typically made of glass and therefore subject to breakage.</span> <span>All components of the distillation apparatus should be protected to a stable stand or rack to avoid it from falling over.</span>
7 0
3 years ago
Which object, A, B, or C would experience the least pull of gravity exerted from the planet? Please use Newton's law to help exp
Assoli18 [71]

What Is the Hubble Space Telescope?
The Hubble Space Telescope is a large telescope in space. NASA launched Hubble in 1990. Hubble is as long as a large school bus. It weighs as much as two adult elephants. Hubble travels around Earth at about 5 miles per second. That is as fast as driving a car from the East Coast of the United States to the West Coast in 10 minutes.

Hubble faces toward space. It takes pictures of planets, stars and galaxies. Hubble has seen stars being born. Hubble has seen stars die. It has seen galaxies that are trillions of miles away. Hubble also has seen comet pieces crash into the gases above Jupiter.

Scientists have learned a lot about space from Hubble pictures. The pictures are beautiful to look at too.


What Makes Hubble Different From Telescopes on Earth?
The mixture of gases that surround a planet is called its atmosphere. Earth's atmosphere changes and blocks some of the light that comes from space. Hubble flies around, or orbits, high above Earth and its atmosphere. So, Hubble can see space better than telescopes on Earth can. Hubble is not the kind of telescope that you look through with your eye.  Hubble uses a digital camera. It takes pictures like a cell phone. Then Hubble uses radio waves to send the pictures through the air back to Earth.


Where Did the Name Hubble Come From?
Hubble is named after Edwin P. Hubble. He was an astronomer. An astronomer is a scientist who studies the planets, stars and space. Edwin P. Hubble made important discoveries about the universe in the early 1900s.


What Is NASA Learning From the Hubble Space Telescope?
Hubble has helped scientists learn about our solar system. The telescope observes comets and planets. Hubble even discovered moons around Pluto that had not been seen before. The telescope has helped scientists understand how planets and galaxies form. Galaxies contain billions of stars. A picture called "Hubble Ultra Deep Field" shows some of the farthest galaxies ever seen. Pictures from Hubble help scientists learn more about the whole universe. Because of Hubble pictures, scientists think the universe is almost 14 billion years old.

Hubble has spotted black holes. Black holes suck in everything around them. They even suck in light. And Hubble has helped scientists learn more about explosions that happen when huge stars burn out.


What Is the Future for Hubble?
In 2009, astronauts flew to Hubble on the space shuttle. This was the fifth time astronauts went to Hubble. They went to fix parts. They also put new parts and cameras in the telescope. So it is working very well. Hubble will not be fixed again. In 2015, Hubble turned 25 years old. It still takes beautiful pictures of objects in space.

NASA is building another space telescope. It is called the James Webb Space Telescope. It will be bigger than Hubble. Webb will not orbit Earth as Hubble does. Webb will orbit the sun in a spot on the other side of the moon. The Webb telescope will be able to see a different kind of light than the light Hubble sees. Webb will help NASA see even more of the universe.

7 0
3 years ago
What is the thinnest film of a coating with n = 1.39 on glass (n=1.52) for which destructive interference of the red component (
Illusion [34]
In optics, you have to create a layer of coating that is approximately 1/4 of the light's wavelength. The working equation for this problem is:

d = λ₀/4n, 
where
λ₀ is the wavelength of the incident light
n is the refractive index of the coating

Substituting the values,

d = (650 nm)/4(1.39)
<em>d = 116.9 nm</em>
8 0
4 years ago
suppose that the man pictured on the front side is orbiting the earth (mass=5.98 x 10^24kg at a distance of 310 miles above the
wlad13 [49]

Answer:

a = 9.81[m/s^2]; v = 18683.5[m/s]

Explanation:

The stament of the problem is:

Suppose that the man pictured on the front side is orbiting the earth (mass = 5.98 x 1024kg) at a distance of 310 miles (1600 meters = 1 mile) above the surface of the earth (radius = 4000 miles).

a. What acceleration does he experience due to the earth's pull?

b. What tangential velocity must he possess in order that he orbit safely (in m/s)?

First we need to convert all the initial data to units of the SI

Rs = 310 [mil] = 498897 [m]

RT= 400 [mil] = 643738 [m]

r = Rs + RT = 1142635 [m] "distance from the center of the earth to the man"

F=G*\frac{M*m}{r^{2} } \\where:\\

G = universal gravitational constant

M = mass of the earth [kg]

m = mass of the man [kg]

r = distance from the center of the earth to the man [m]

a)

The acceleration he is experimenting is the same acceleration given by the gravity, therefore:

a = g = 9.81[m/s^2]

b)

To find the tangential velocity, we must determinate the force exerted by the earth.

Now we will find the force exerted by the gravity when the man is orbiting the earth at distance r.

G = 6.67*10^{-11} [\frac{N*m^{2} }{kg^{2} } ]\\M=5.98*10^{24}[kg]\\ m=100 [kg]\\Replacing:\\F = G*\frac{M*m}{r^{2} }

F = 6.67*10^{-11}*\frac{5.98*10^{24}*100 }{1142635^{2} } \\ F= 30550 [N]

And this force will be equal to the following expression:

F = m*\frac{v^{2} }{r} \\where:\\v= tangential velocity [m/s]\\v=\sqrt{\frac{F*r}{m} } \\v=\sqrt{\frac{30550*1142635}{100} } \\v=18683.5[m/s]

8 0
3 years ago
Suppose you are helping Galileo measure the acceleration due to gravity by dropping a canon ball from the tower of Pisa, You mea
Anni [7]

It is given that the height of the tower is

h=183 ft.

The uncertainty the measurement of this height is

\Delta h=0.2 ft

Drop time is measured as:

t=3.5s

The uncertainty in measurement of time is:

\Delta t=0.5 s

Using the equation of motion: h=ut+\frac{1}{2} at^2 where, h is the distance covered, u is the initial velocity, a is the acceleration and t is the time.

u=0 (because canon ball is in free fall). we need to calculate the value of a=g.

\Rightarrow h=\frac{1}{2}gt^2

\Rightarrow g=\frac{2h}{t^2}\\ \Rightarrow g=\frac{2\times 183ft}{(3.5s)^2}=29.87 ft/s^2

The uncertainty in this value is given by:

\Delta g=g\sqrt{(\frac{\Delta h}{h})^2+(\frac{2\Delta t}{t})^2}

Substitute the values:

\Delta g=29.87\sqrt{(\frac{0.2 }{183})^2+(\frac{2\times 0.5}{3.5})^2}=29.87\sqrt{1.19\times 10^{-6}+0.08}=29.87\times \sqrt{0.08}=29.87\times 0.28=8.44 ft/s^2



5 0
4 years ago
Other questions:
  • Consider the two-body situation at the right. A 3.50x103-kg crate (m1) rests on an inclined plane and is connected by a cable to
    11·1 answer
  • An earth satellite remains in orbit at a distance of 13300 km from the center of the earth. what is its period? the universal gr
    15·1 answer
  • What causes long sightedness?how is it corrected.
    14·1 answer
  • Which is true about surface waves?
    8·2 answers
  • What would be the physical sign that a bone CANNOT continue longitudinal growth? What would be the physical sign that a bone CAN
    10·2 answers
  • 1. In which direction can a force be exerted on an object?
    11·1 answer
  • What is the charge of a Sulfur atom if it has 17 electrons?
    12·1 answer
  • Einstein calculated that ripples of gravity travel at exactly the speed of _____
    11·1 answer
  • Calculate the drop voltage for a battery of internal resistance 2 ohm and emf of 24 volt
    10·1 answer
  • CORRECT ANSWER WILL BE REWARDED BRAINLIEST
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!