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12345 [234]
3 years ago
9

Which are characteristics of refraction? Check all that apply.

Physics
2 answers:
vagabundo [1.1K]3 years ago
5 0

Answer:

2, 3, 5

Explanation:

I just did this

Taya2010 [7]3 years ago
4 0
The answer is 2,3 & 5 i put 1,3,5 like someone else put but got it wrong, its 2,3 & 5
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The radiation per unit area from the Sun reaching the earth is 1400 W/m2 , approximately the amount of radiative power per unit
natka813 [3]

Answer:

83.2 W/m^2

Explanation:

The radiation per unit area of a star is directly proportional to the power emitted, which is given by Stefan-Boltzmann law:

P=\sigma A T^4

where

\sigma is the Stefan-Boltzmann constant

A is the surface area

T is the surface temperature

So, we see that the radiation per unit area is proportional to the fourth power of the temperature:

I \propto T^4

So in our problem we can write:

I_1 : T_1^4 = I_2 : T_2^4

where

I_1 = 1400 W/m^2 is the power per unit area of the present sun

T_1 = 5800 K is the temperature of the sun

I_2 is the power per unit area of sun X

T_2 = 2864 K is the temperature of sun X

Solving for I2, we find

I_2 = \frac{I_1 T_2^4}{T_1^4}=\frac{(1400 W/m^2)(2864 K)^4}{(5800 K)^4}=83.2 W/m^2

6 0
3 years ago
How do you calculate acceleration
Eduardwww [97]

Answer: acceleration is equal to the change in velocity per unit time in seconds.

a= ∆v / t = vf - vi / t

Explanation: change in velocity or ∆v can be expressed as (vf - vi)

7 0
2 years ago
A jogger runs by a river with a velocity of 7 m s relative to the ground. A leaf floating on the river moves with a velocity of
Hunter-Best [27]

Answer:

The velocity of the leaf relative to the jogger is 5 m/s.                    

Explanation:

Given that,

Velocity of jogger wrt to the ground, V_j=7\ m/s

velocity of leaf wrt the ground, v_i=2\ m/s

We need to find the velocity of the leaf relative to the jogger. Let it is equal to V. So, it is given by :

V=v_j-v_i\\\\V=7-2\\\\V=5\ m/s

So, the velocity of the leaf relative to the jogger is 5 m/s. Hence, this is the required solution.

3 0
3 years ago
HNJTYNTYHYHGYHY6HYHY5HTH
Ipatiy [6.2K]

Answer:

Explanation:

fvtgyn

3 0
3 years ago
Read 2 more answers
Compare the force of air resistance and the force of gravity on an object falling at its terminal velocity.
Sholpan [36]
The viscous force on an object moving through air is proportional to its velocity.
The only forces acting on an object when falling are air resistance and its weight itself. The weight acts vertically downwards whereas air resistance acts vertically upward.
Let F be the viscous force due to air molecules, B be buoyant force due to air and W be the weight of falling object. Initially, the velocity of falling object and hence the viscous force F is zero and the object is accelerated due to force
(W-B). Because of the acceleration the velocity increases and accordingly the viscous force also increases. At a certain instant, the viscous force becomes equal to W-B. The net force then becomes zero and the object falls with constant velocity. This constant velocity is called terminal velocity.
Thus at terminal velocity, air resistance and force of gravity becomes equal.
7 0
3 years ago
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