The x -component of the object's acceleration is 2 m/s².
<h3>What's the resultant force along x- direction?</h3>
- Forces along x axis direction are as follows
- 4N along +x axis, so it's taken as +4 N
- 2N along -x axis , so it's taken as -2N.
- Resultant force along x direction = 4N - 2N = 2 N which is along + ve x direction.
<h3>What's the acceleration along x axis direction?</h3>
- As per Newton's second law, Force = mass × acceleration of the object
- Force along x axis= mass × acceleration along x axis= 2N
- Acceleration = 2/ mass = 2/1 = 2 m/s²
Thus, we can conclude that the acceleration along x axis is 2 m/s².
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The forces in (Figure 1) are acting on a 1.0 kg object. What is ax, the x-component of the object's acceleration?
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I think the answer would be 70
Answer:
The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.
Explanation:
It is given that,
Mass of the box, m = 2.2 kg
The box is inclined at an angle of 30 degrees
Vertical distance, d = 3.1 m
The coefficient of friction,
Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.
W is the work done by the friction.
v = 8.19 m/s
So, the speed of the box is 8.19 m/s. Hence, this is the required solution.
Answer:
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Explanation:
Given:
- mass of particle A,
- mass of particle B,
- mass of particle C,
- All the three particles lie on a straight line.
- Distance between particle A and B,
- Distance between particle B and C,
Since the gravitational force is attractive in nature it will add up when enacted from the same direction.
<u>Force on particle A due to particles B & C:</u>
<u>Force on particle C due to particles B & A:</u>
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<u>Force on particle B due to particles C & A:</u>
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