The element number of Fe is 26, which means that the number of neutrons of the following isotopes is:
<span>53-Fe: 27 </span>
<span>54-Fe: 28 </span>
<span>56-Fe: 30 </span>
<span>57-Fe: 31 </span>
<span>58-Fe: 32 </span>
<span>59-Fe: 33 </span>
<span>Because 53-Fe has too few neutrons when compared to the other isotopes we can rule out any decay that involves losing a neutron: (alpha decay, beta decay) So, this isotope will prefer to decay by electron capture or positron emission (assuming the system has about 1 MeV to spare), but in each case the product will be the same: 53-Mn (long-lived radioisotope). </span>
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I believe the answer would be A. A pea is to a pod
Answer:
The higher the temperature, the more soluble most ionic solids are in water
As you cool a saturated solution from high temperature to low temperature, solids start to crystallize out of solution if you achieve a supersaturated solution.
If you raise the temperature of a saturated solution, you can (usually) add more solute and make the solution even more concentrated.
Explanation:
For many ionic solids, solubility in water increases with increase in the temperature of the solution.
This implies that increasing the temperature allow more solute to dissolve in the solvent, supersaturation may be achieved by so doing. As the solution is cooled, the solid crystalizes out of solution hence the answers above.