Answer: The IUPAC name of propan-2-one and is pentan-2-one.
Explanation:
The basic rules for naming of organic compounds are :
1. First select the longest possible carbon chain. The longest possible carbon chain should include the carbons of double or triple bonds or functional group.For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
2. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and ketones by adding the suffix -one.;
3. The numbering is done in such a way that the carbon containing the functional group gets the lowest number. While writing the name, the word root is given first , followed by the position of carbon containing the functional group followed by the suffix.
The IUPAC name of propan-2-one and is pentan-2-one.
Answer: 0.4M
Explanation:
This would be much easier if we first analized what was given from the question. This is illustrated below:
C1 = 2M
V1 = 25mL
C2 =?
V2 = 125mL
C1V1 = C2V2
2x25= C2 x 125
Divide both side by 125, we have:
C2 = (2x25) /125
C2 = 0.4M
Therefore, the molarity of potassium bromide formed will be 0.4M
The change is thermal energy to chemical energy. Sugar contains a lot of chemical potential energy which is why living things use it as a source of energy. The process of photo synthesis takes light from the sun to convert carbon dioxide and water into sugar and oxygen. That process is basically turning the thermal energy from the light into chemical energy in the sugar.
48.78%
Percentage of MgSO4 = mass of MgSO4/ mass of sample (MgSO4. 7H20) and multiply it by 100.