Step-by-step explanation:
<em>G</em><em>iven,</em>
<em>no.</em><em> </em><em>of </em><em>students</em><em> </em><em>ride </em><em>bikes </em><em>to </em><em>school</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>students</em><em> </em><em>out </em><em>of </em><em>3</em><em>2</em>
<em>no.</em><em> </em><em>of </em><em>students</em><em> </em><em>ride </em><em>bikes </em><em>to </em><em>school </em><em>out </em><em>of </em><em>8</em><em>0</em><em>0</em><em> </em><em>students,</em>
<em>a/</em><em>q </em><em>the </em><em>equation</em><em> </em><em>is,</em>
<em></em>
<em>therefore,</em><em> </em><em>1</em><em>2</em><em>5</em><em> </em><em>out </em><em>of </em><em>8</em><em>0</em><em>0</em><em> </em><em>studen</em><em>t</em><em>s </em><em>rude </em><em>bikes </em><em>to </em><em>school!</em>
<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>you </u></em><em><u>dear!</u></em>
Answer:
the answer is 0,-180
Step-by-step explanation:
The integers are x, x + 2 and x + 4
x + x + 2 + x + 4 = 72
3x + 6 = 72
3x = 72 - 6 = 66
x = 66/3 = 22
The least consecutive integer is 22
The second consecutive integer is 24
Therefore, the numbers are 22, 24 and 26
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
Alrighty, so, If I remember correctly: I believe the answer you're looking for is 5.76 x 10^3
Imagine there's a decimal after the zero. You can only have one integer in FRONT of the decimal therefore you move your decimal 3 places to the left. This gives you 5.76 x 10^3 because you always remove the zero when it's at the end of the number.
Hope this helps!