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2 years ago

Which equation in point slope form describes the line that passes through (3,-5) and has a slope of 2?

Mathematics

1 answer:

slava [35]2 years ago

8 0

Answer:

y + 5 = 2(x - 3)

General Formulas and Concepts:

Algebra I

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate
y₁ - y coordinate
m - slope

Step-by-step explanation:

Step 1: Define

Point (3, -5)

Slope m = 2

Step 2: Write equation

Substitute in variables into the general form.

y + 5 = 2(x - 3)

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Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Solution:

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

2 years ago

The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste and 2460 dollars for 135 kg of waste. (a)

Ulleksa [173]

Answer:

$C=18w+30$

Step-by-step explanation:

We are given that The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste

So, $(x_1,y_1)=(100,1830)$

We are also given that The monthly charge for a waste collection service is 2460 dollars for 135 kg of waste.

So, $(x_2,y_2)=(135,2460)$

We are supposed to find a linear model for the cost, C, of waste collection as a function of the number of kilograms, w.

So, we will use two point slope form :

Formula : $y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Substitute the values

$y-1830=\frac{2460-1830}{135-100}(x-100)$

$y-1830=18(x-100)$

$y-1830=18x-1800$

$y=18x-1800+1830$

$y=18x+30$

y denotes the cost

x denotes the weight

So, Replace y with C and x with w

$C=18w+30$

So, a linear model for the cost, C, of waste collection as a function of the number of kilograms, w is $C=18w+30$

7 0

2 years ago

What is the value of expression below 56 ÷ 1/17

Mariulka [41]

$56 \div \frac{1}{17} \\ = 56 \times \frac{17}{1} \\ = 56 \times 17 \\ = 952$

Hope this helps.

4 0

2 years ago

G(x)=x^2-2,find the range for the domain

solong [7]

Range:[-2,8)
That’s the range for the domain down below

7 0

2 years ago

Please help me with this math problem.

NARA [144]

WHERE IS THE MATH PROBLEM

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2 years ago