Make a game plan. ...
Make up numbers for segments and angles. ...
Look for congruent triangles (and keep CPCTC in mind). ...
Try to find isosceles triangles. ...
Look for parallel lines. ...
Look for radii and draw more radii. ...
Use all the givens.
Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
0.375
Step-by-step explanation:
Answer:
The Area of Rectangular Garden is 1044 feet²
Step-by-step explanation:
According to question
The perimeter of the garden = 82 ft
Let the length be L ft
The width be W ft
Now as per question
L = 5 + ( 2× W )
∵ Perimeter of Rectangle = 2 × ( Length + Width )
Or , Perimeter of Rectangle = 2 × ( L+ W )
Or, 82 = 2 × ( L+ W )
Or, 82 = 2 × [ 5 + ( 2 ×W ) + W ) ]
Or, 82 = 2 × ( 5 +3W )
Or, 41 = 5 + 3W
Or, 41 - 5 = 3W
So, 3W= 36
∴ W =
= 12 feet
I.e Width = 12 feet
And L = 5 + ( 2× W )
Or, Length = 5 + 24 = 29 feet
Now The Area of Rectangle = Length × width
So, The Area of Rectangle = 29 ft × 36 ft
The Area of Rectangle is 1044 feet²
Hence The Area of Rectangular Garden is 1044 feet² Answer
Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>
From eqn 3,
d = 30 - 12
<h3>d = 18</h3>
Thus she has 18 dimes and 12 quarters