Which of the following best characterizes the field of physics

The soccer game begins with a ______ ______ in the center of the field

blagie [28]

It begins with a kick-off

6 0

3 years ago

I. How does The Bhutan Forest Act of 1969, affect the lives of shifting cultivators?

ZanzabumX [31]

The Bhutan Forest Act of 1969, affect the lives of shifting cultivators because the act placed the status of Tsheri land on the same footing with wetland and rain-fed land.

<h3>What is shifting cultivators?</h3>

A field that had been developed whenever was left neglected for quite a long time, Shifting cultivators were tracked down in the sloping and forested lots of North-east and Central India. The existences of these ancestral individuals relied upon free development inside backwoods and on having the option to involve the land and woods for developing their harvests.

The Forest Act of 1969 has restricted new clearances for moving development however has not deterred the act of it where such development doesn't jeopardize the wellbeing of the roadway and public property. The Land Act of 1979 has put the situation with
Tsheri land on a similar footing with wetland and rain fed land.

Thus, Bhutan Forest Act of 1969, affect the lives of shifting cultivators.

Learn more about shifting cultivators

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8 0

2 years ago

hallar un numero de dos cifras sabiendo que la suma de las cifras es 12 y que la primera de ellas es el triple de la segunda

Natali [406]

Answer:

93 o 39.

Explanation:

Hola.

En este caso, podemos resolver este problema por medio del planteamiento de las siguientes ecuaciones:

1. Definimos x como el primer dígito y y como el segundo, por lo tanto, como su suma es 12, escribimos:

x + y = 12

2. Ahora, dado que el primer dígito, x es el triple del segundo, escribimos:

x = 3 y

De este modo, podemos resolver para y:

3 y + y = 12

4 y = 12

y = 12 / 4

y = 3

Y para x:

x = 3 y

x = 3 * 3

x = 9

Así, el número puede ser 93 o 39.

¡Saludos!

3 0

3 years ago

(100 POINTS!!!!!) What type of solar radiation does not reach the surface of the Earth?

Kobotan [32]

Gamma radiations do not reach the surface of the Earth

Explanation:

Sun radiates all of these radiations but one of them does not reach the surface of the Earth. Most of the radiation switch reaching the Earth's surface are visible and infrared radiations.

8 0

3 years ago

From the edge of a cliff, a 0.55 kg projectile is launched with an initial kinetic energy of 1550 J. The projectile's maximum up

IrinaVladis [17]

Answer:

(a) 38.5m/s

(b) 64.4m/s

Explanation:

First, we can obtain the launch speed from the definition of kinetic energy:

$K=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{2K}{m}}\\\\$

Plugging in the given values, we obtain:

$v=\sqrt{\frac{2(1550J)}{0.55kg}}\\\\v=75.0m/s$

Now, from the conservation of mechanical energy, considering the instant of launch and the instant of maximum height, we get:

$E_0=E_f\\\\K_0=U_g_f+K_f\\\\\frac{1}{2}mv_0^2=mgh_f+\frac{1}{2}mv_0_x^2\\\\\frac{1}{2}mv_0^2=mgh_f+\frac{1}{2}mv_0^2\cos^2\theta\\\\\implies \cos\theta=\sqrt{1-\frac{2gh_f}{v_0^2}}$

And with the known values, we compute:

$\cos\theta=\sqrt{1-\frac{2(9.8m/s^2)(140m)}{(75.0m/s)^2}}\\\\\cos\theta=0.513\\\\\theta=59.12\°$

Finally, to know the components of the launch velocity, we use trigonometry:

$v_0_x=v_0\cos\theta=(75.0m/s)\cos(59.12\°)=38.5m/s\\\\v_0_y=v_0\sin\theta=(75.0m/s)\sin(59.12\°)=64.4m/s$

It means that the horizontal component of the launch velocity is 38.5m/s (a) and the vertical component is 64.4m/s (b).

8 0

3 years ago