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crimeas [40]
2 years ago
14

Vestobular receptors enable one to balance. True or False

Physics
2 answers:
frozen [14]2 years ago
5 0
The answer is actually true. i just took the test and i put false and it was wrong
olga2289 [7]2 years ago
5 0

Answer:

The given statement is true.

In most of the animals, the vestibular system contributes to the spatial orientation and sense of balance.

It helps in coordinating movement with balance.

The vestibular system is composed of two components semi-circular canals and otoliths.

Rotational movements are indicated by semi-circular canals whereas linear accelerations are indicated by Otoliths.

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An underwater scuba diver sees the Sun at an apparent angle of 43.0° above the horizontal. What is the actual elevation angle of
Inessa05 [86]

Answer:

The actual elevation angle is 12.87 degrees

Explanation:

In the attachment you can clearly see the situation. The angle of elevation as seen for the scuba diver is shown in magenta, we conclude that \theta_2=90-43=47.

Using Snell's Law we can write:

n_1\sin(\theta_1)=n_2\sin(\theta_2)

\implies \sin(\theta_1)=\frac{n_2}{n_1}\sin(\theta_2),

Let's approximate the index of refraction of the air (medium 1 in the picture) to 1.

We thus have:

\sin(\theta_1)=n_2\sin(\theta_2)=1.333\sin(47)

\implies\theta_1=\arcsin[n_2\sin(\theta_2)]=\arcsin[1.333\sin(47)]\approx 77.13. Calling \alpha the actual angle of elevation, we get from the picture that \alpha=90-77.13=12.97

7 0
2 years ago
NO LINKS
zhenek [66]

Answer: A , D & F

Explanation:

6 0
2 years ago
The electric motor of a model train accelerates the train from rest to 0.685 m/s in 21.5 ms. The total mass of the train is 875
Natali [406]

Answer:

P=9.58 W

Explanation:

According to Newton's second law, and assuming friction force as zero:

F_m=m.a\\F_m=0.875kg*a

The acceleration is given by:

a=\frac{\Delta v}{t}\\a=\frac{0.685m/s}{21.5*10^{-3}s}\\\\a=31.9m/s^2

So the force exerted  by the motor is:

F_m=0.875kg*31.9m/s^2\\F_m=27.9N

The work done by the motor is given by:

W_m=F_m*d\\\\d=\frac{1}{2}*a*t^2\\d=\frac{1}{2}*31.9m/s^2*(21.5*10^{-3}s)^2\\\\d=7.37*10^{-3}m

W_m=27.9N*7.37*10^{-3}m\\W_m=0.206J

And finally, the power is given by:

P=\frac{W_m}{t}\\P=\frac{0.206J}{21.5*10^{-3}s}\\\\P=9.58W

8 0
3 years ago
In an electrostatic field, path 1 between points A and B is twice as long as path 2. The electrostatic work done on a negatively
Elanso [62]

Answer:

W2 = W1

Explanation:

work is independent of the path taken between the points.

8 0
2 years ago
An aluminum bar 600mm long, with diameter 40mm long has a hole drilled in the center of the bar.The hole is 30mm in diameter and
Svetradugi [14.3K]

Answer:

Total contraction on the Bar  = 1.22786 mm

Explanation:

Given that:

Total Length for aluminum bar = 600 mm  

Diameter for aluminum bar  = 40 mm

Hole diameter  = 30 mm

Hole length = 100 mm

elasticity for the aluminum is 85GN/m² = 85 × 10³ N/mm²

compressive load P = 180 KN = 180  × 10³ N

Calculate the total contraction on the bar = ???

The relation used in  calculating the contraction on the bar is:

\delta L = \dfrac{P *L }{A*E}

The relation used in  calculating the total contraction on the bar can be expressed as :

Total contraction in the Bar = (contraction in part of bar without hole + contraction in part of bar with hole)

i.e

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Let's find the area of cross section without the hole and with the hole

Area of cross section without the hole is :

Using A = πd²/4

A = π (40)²/4

A = 1256.64 mm²

Area of cross section with the hole is :

A = π (40²-30²)/4

A = 549.78 mm²

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Total contraction on the Bar  = \dfrac{180 *10^3 \N  }{85*10^3 \ N/mm^2} [\dfrac{500}{1256.64}+ \dfrac{100}{549.78}]

Total contraction on the Bar  = 2.117( 0.398 + 0.182)

Total contraction on the Bar  = 2.117*(0.58)

Total contraction on the Bar  = 1.22786 mm

5 0
3 years ago
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