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natali 33 [55]
3 years ago
14

A 7.0 kg box is at rest on a table. The static friction coefficient jis between the box and table is 0.40, and

Physics
1 answer:
Neko [114]3 years ago
8 0

Answer:

A m 23 3.3 32 m 0.37

Explanation:

So ur still thinking of me Just like I know you should. I cant not give you everything You know I wish I could.

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Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude
aivan3 [116]

Answer:

E=6.8Kv/m

Explanation:

From the question we are told that

Distance b/w plate d=10cm=>0.1m

P_1 Potential at 7.35 V=533v

Generally the equation for electric field at a distance is mathematically given as

E=\frac{v}{d}

E=\frac{533}{7.85*10^-^2}

E=6789.808917

E=6.8*10^3

E=6.8Kv/m

7 0
3 years ago
Andre, whose mass is 77.1 kg, sits on a diving board above a dunk tank. If he is sitting 0.90 m above the water, what is his tot
Ganezh [65]

Answer:

680 J

Explanation:

Mechanical energy = potential energy + kinetic energy

ME = PE + KE

ME = mgh + ½ mv²

ME = (77.1 kg) (9.8 m/s²) (0.90 m) + ½ (77.1 kg) (0 m/s)²

ME = 680 J

8 0
3 years ago
Read 2 more answers
Select all that apply. Which of the following do not illustrate a complete circuit? A B C D
ipn [44]
There is not enough information here.
7 0
3 years ago
Read 2 more answers
If the speed of a car is 20m/s .How long does it take to cover a distance of 1km?<br>​
3241004551 [841]

Answer: 50 seconds

Explanation:

1km=1000m

Distance/speed=time

1000/20=50

50 seconds

7 0
3 years ago
Read 2 more answers
water has an index of refraction of 1.33. What is the critical angle for light leaving a pool of water into air? 0 37 90 49
vesna_86 [32]
When light travels from a medium with higher refractive index into a medium with lower refractive index, there is a maximum angle (called critical angle) for which all the light is reflected, so there is no refraction.

The value of the critical angle is given by:
\theta = \arcsin ( \frac{n_2}{n_1} )
when n1 is the refractive index of the first medium, while n2 is the refractive index of the second medium. In our case, n1=1.33 (the water) and n1=1.00 (the air). Putting numbers in, we get
\theta = \arcsin ( \frac{1.00}{1.33} )=49^{\circ}
6 0
3 years ago
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