All categories

3 years ago

Please answer me without spamming

Mathematics

1 answer:

brilliants [131]3 years ago

6 0

THE ANSWER :- h = 93.88 cm

Step by step:-

You might be interested in

Select the best answer for the question.

Marat540 [252]

The answer of this question is 42

3 0

3 years ago

I WILL GIVE BRAINLIEST!!!!!!

katovenus [111]

Answer:

I think Quadrant 1. I;m not trying to just answer for the points

Step-by-step explanation:

5 0

3 years ago

How do I create an equivalent expression that includes parentheses so that the value of the expression is 2 for 3+8-4x2-12

natka813 [3]

(3+8-4)×2-12
3+8=11
11-4=7
7×2=14
14-12=2

5 0

3 years ago

Solve equation: 15=2y - 5(quickly please)

andrew11 [14]

15+5=2y-5+5

=20 = 2y

20/2 = 2y/2

10 = y

5 0

3 years ago

Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi

Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

The formula to compute covariance is:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

The formula to compute the variances are:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}$

Consider the table attached below.

Compute the covariance as follows:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

$=(5\times 165)-(30\times 25)\\=75$

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50$

Compute the correlation coefficient as follows:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

$=\frac{75}{\sqrt{230\times 50}}$

$=0.69937\\\approx0.70$

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0

3 years ago