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3 years ago

Please answer. Thank you

Chemistry

1 answer:

amm18123 years ago

3 0

Answer:

Explanation:

what are tho anwser choices

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Ca(s) + O2(g) - O A. Cao(s) B. Ca2O(s) O C. 2Ca(s) + O2(g) O D. CaO2(s)

Pepsi [2]

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3 years ago

andreev551 [17]

Answer:

it is b just trust me man I know

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3 years ago

Read 2 more answers

In which type of condition is a conditions is a landslide most likely to occur

masha68 [24]

Answer:

B. In a wet, hilly area

Explanation:

We know that for a landslide to happen, there has to be a down hill slope so it can fall.

This eliminates answers C, D and E.

So we are left with A and B

Now we can look at this in a real life scenario. If you have ever walking on wet ground, you will know that is weaker than dry ground. Knowing this, we know the answer will have to be answer B.

6 0

3 years ago

Question 1: Investigate the effect of forces on various objects. What is the hypothesis:

blagie [28]

Answer:

It is a proposed explanation for a phenomenon.

4 0

3 years ago

The natural distribution of the isotopes of a hypothetical element is 60.795% at a mass of 281.99481 u, 22.122% at a mass of 283

fenix001 [56]

Answer: The average atomic mass of the element is 283.291 amu

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

For isotope 1:

Mass of isotope 1 = 281.99481 amu

Percentage abundance of isotope 1 = 60.795 %

Fractional abundance of isotope 1 = 0.60795

For isotope 2:

Mass of isotope 2 = 283.99570 amu

Percentage abundance of isotope 2 = 22.122 %

Fractional abundance of isotope 2 = 0.22122

For isotope 3:

Mass of isotope 3 = 286.99423 amu

Percentage abundance of isotope 3 = [100 - (60.795 + 22.122)] = 17.083 %

Fractional abundance of isotope 1 = 0.17083

Putting values in equation 1, we get:

$\text{Average atomic mass of element}=[(281.99481\times 0.60795)+(283.99570\times 0.22122)+(286.99423\times 0.17083)]\\\\\text{Average atomic mass of element}=283.291amu$

Hence, the average atomic mass of the element is 283.291 amu

5 0

4 years ago