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fenix001 [56]
3 years ago
5

The milky way galaxy is the galaxy that is closest to us contains the most stars is farthest from us contains our solar system

Physics
1 answer:
yKpoI14uk [10]3 years ago
6 0
The Milky Way galaxy is the one that the sun is a member of, and it contains
our solar system.  We're in it, and you can't get much closer than that.

The Milky Way is known to be bigger than your average galaxy, but it's
probably not correct to say that it contains the 'most' stars of any galaxy. 
The estimate for the Milky Way is only a few hundred billion stars.
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The ink drops have a mass m = 1.00×10^−11 kg each and leave the nozzle and travel horizontally toward the paper at velocity v =
luda_lava [24]

Answer:

9.98 × 10⁻⁹ C

Explanation:

mass, m = 1.00 × 10⁻¹¹ kg

Velocity, v = 23.0 m/s

Length of plates D₀ = 1.80 cm = 0.018 m

Magnitude of electric field, E = 8.20 × 10⁴ N/C

drop is to be deflected a distance d = 0.290 mm = 0.290 × 10⁻³ m

density of the ink drop = 1000 kg/m^3

Now,

Time = \frac{\textup{Distance}}{\textup{Velocity}}

or

Time = \frac{\textup{0.016}}{\textup{23}}

or

Time = 6.9 × 10⁻⁴ s

Now, force due to the electric field, F = q × E

where, q is the charge

Also, Force = Mass × acceleration

q × E = 1.00 × 10⁻¹¹ × a

or

a = \frac{q\times8.20\times10^4}{1\times10^{-11}}

Now from the Newton's equation of motion

d=ut+\frac{1}{2}at^2

where,  

d is the distance

u is the initial speed  

a is the acceleration

t is the time

or

0.290\times10^{-3}=0\times(6.9\times10^{-4})+\frac{1}{2}\times(\frac{q\times8.20\times10^4}{1\times10^{-11}})\times(6.9\times10^{-4})^2

or

q = 9.98 × 10⁻⁹ C

4 0
3 years ago
2.Cars were previously manufactured to be as sturdy as possible, whereas today's cars
Marina CMI [18]

Answer:

Crumple zones are designed to absorb and redistribute the force of a collision. ... Also known as a crush zone, crumple zones are areas of a vehicle that are designed to deform and crumple in a collision. This absorbs some of the energy of the impact, preventing it from being transmitted to the occupants.

4 0
3 years ago
A sailboat sits tied up at the dock.
shutvik [7]

Answer:B

Explanation:i think so im not suree

5 0
3 years ago
If two point masses 1kg & 4kg are seperated by a distance of 2m. Magnitude of gravitational force exerted by 1kg on 4kg is ?
Aliun [14]

Answer:

  • F = G Newtons

Explanation:

Given:

  • Mass of 1st body = 1\:kg
  • Mass of 2nd body = 4\:kg

To Find:

  • Magnitude of gravitational force

Solution:

Here, we have a formula

  • F=\dfrac{G.M_{1}.M_{2}}{r^{2}}

<u>Substituting the values</u>

\implies\:\:F = \dfrac{G(1)(4)}{2^{2}}

\implies\:\:F = \dfrac{4G}{4}

\implies\:\:F = \dfrac{\cancel{4}G}{\cancel{4}}

\implies\:\:\red{F = G}

Know More:

The applied formula for the above solution is

{\boxed{F_{G}=\dfrac{G.M_{1}.M_{2}}{r^{2}}}}

where,

  • F_{G} = Gravitational force
  • G = Gravitational constant
  • M_{1} = mass of 1st body
  • M_{2} = mass of 2nd body
  • r = distance between two bodies
6 0
3 years ago
A 1500 kg truck travelling north at 60 km/hr collides with a 1200 kg car moving east at 15km/hr. If the two cars remain locked t
Alenkinab [10]

Answer:

33.33j+6.67i km/hr

Explanation:

From the law of conservation of momentum,

Applying,

mu+m'u' = V(m+m')............... Equation 1

Where m = mass of the truck, m' = mass of the car, u = initial velocity of the truck, u' = initial velocity of the car, V = Final velocity.

Note: let j represent the north, and i  represent the east

From the question,

Given: m = 1500 kg, u = 60j, m' = 1200 kg, u' = 15i

Substitute these values into equation 1

1500*60j+1200*15i = V(1500+1200)

90000j+18000i = 2700V

V = (90000j+18000i)/2700

V = 33.33j+6.67i km/hr

6 0
3 years ago
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