10 pairs of 40 because 4 times 10 is 40
F(0)= 4
if you plug 0 in for the x -3 multiplied by 0 equals 0 plus 4 equals 4
First, find the z-score:
z = (value - mean) / sdev
= (275 - 280) / 15
= - 0.33
In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)
Looking at the table, we find P(z < 0.33) = 0.6293
Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707
Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>
Answer:
40.4%
Step-by-step explanation:
Given data
Initial depth= 5feet
Final depth= 5-3.2+6.6= 8.4feet
Hence the percent change
% change= FInal-initial/final*100
% change= 8.4-5/8.4*100
% change= 3.4/8.4*100
% change= 0.404*100
% change=40.4%
Hence the percent change is 40.4%