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Aleksandr [31]
3 years ago
7

A standing wave is a wave that travels through space indefinitely. True or false

Physics
1 answer:
Step2247 [10]3 years ago
4 0
A standing wave is a wave that travels through space indefinitely.: 
<span>False.
</span>
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A plot of land has been surveyed for a new housing development with borders AB, BC, DC, and DA. The plot of land is a right trap
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Angle ABC is 119

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When we move from 100x total magnification to 400x total magnification on a compound light microscope, what happens with resolut
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1. a) In order to sharpen the objective with a 40x objective (400x total magnification), the objective must be closer to the sample than with a 10x objective (100x total magnification), so the sample is out of focus.

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5 0
2 years ago
Assume that the upward direction is positive and the downward direction is negative. What is the ball's velocity (in m/s) when i
LenaWriter [7]

The given question is incomplete. The complete question is as follows.

You throw a ball vertically upward, and as it leaves your hand, its speed is 26.0 m/s.

(a) How high (in m) does it rise above the level where it leaves your hand?

(b) How long (in s) does it take to reach its highest point?

(c) How long (in s) does the ball take to return to the level where it left your hand after it reaches its highest point?

(d) Assume that the upward direction is positive and the downward direction is negative. What is the ball's velocity (in m/s) when it returns to the level where it left your hand? (Indicate the direction with the sign of your answer.)

Explanation:

(a) For maximum height, the formula will be as follows.

           v^{2} = u^{2} + 2as

                 a = v^{2} - 2gh

or,                 h = \frac{v^{2}}{2g}

                        = \frac{(26)^{2}}{2 \times 9.8}

                        = \frac{676}{19.6}

                        = 34.5 m/s

Hence, it rises 34.5 m/s above the level where it leaves your hand.

(b) Time to reach maximum height is as follows.

            v = u + at

or,           v - gt = 0

                 t = \frac{v}{g}

                   = \frac{26}{10}

                   = 2.6 sec

Therefore, it will take 2.6 sec to reach its highest point.

(c)  Time taken by the ball to ascent is equal to the time it has taken to descent.

Therefore, time taken by the ball to return to the level where it left your hand after it reaches its highest point? is also 2.6 sec.

(d)  Speed of the ball will be 26 m/s in the downward direction. Hence, the velocity will be -26 m/s.

3 0
3 years ago
Need help to get this question right!!
Charra [1.4K]

Answer:

16 times as strong

Explanation:

From the question given above, the following assumptions were made:

Initial Force (F₁) = F

Initial distance apart (r₁) = r

Final distance apart (r₂) = ¼r

Final force (F₂) =?

Next, we shall obtain a relationship between the force and the distance apart. This can be obtained as follow:

F = GM₁M₂ / r²

Cross multiply

Fr² = GM₁M₂

If G, M₁ and M₂ are kept constant, then,

F₁r₁² = F₂r₂²

Finally, we determine the new force as follow:

Initial Force (F₁) = F

Initial distance apart (r₁) = r

Final distance apart (r₂) = ¼r

Final force (F₂) =?

Fr² = F₂ × (¼r)²

Fr² = F₂ × r²/16

Fr² = F₂r² / 16

Cross multiply

16Fr² = F₂r²

Divide both side by r²

F₂ = 16Fr² / r²

F₂ = 16F

From the calculations made above, we can see that the new force is 16 times the original force.

Thus, the new force is 16 times stronger.

8 0
3 years ago
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