A.) Electrons are Shared in a covalent bond.
Answer:
0.358Kg
Explanation:
The potential energy in the spring at full compression = the initial kinetic energy of the bullet/block system
0.5Ke^2 = 0.5Mv^2
0.5(205)(0.35)^2 = 12.56 J = 0.5(M + 0.0115)v^2
Using conservation of momentum between the bullet and the block
0.0115(265) = (M + 0.0115)v
3.0475 = (M + 0.0115)v
v = 3.0475/(M + 0.0115)
plugging into Energy equation
12.56 = 0.5(M + 0.0115)(3.0475)^2/(M + 0.0115)^2
12.56 = 0.5 × 3.0475^2 / ( M + 0.0115 )
12.56 = 0.5 × 9.2872/ M + 0.0115
12.56 = 4.6436/ M + 0.0115
12.56 ( M + 0.0115 ) = 4.6436
12.56M + 0.1444 = 4.6436
12.56M = 4.6436 - 0.1444
12.56 M = 4.4992
M = 4.4992÷12.56
M = 0.358 Kg
Answer:10cm3
Explanation:Volume Al = (27g Al)/(2.70g/cm3 Al) = 10cm3 Al. So, 27g of Al has a volume of 10cm3. *
The aluminum atom_loses_____electrons to form an ion.
The ion that is formed is_Al³⁺_____.
aluminium has the electronic configuration as 1s² 2s² 2p⁶ 3s² 3p¹
from the electronic configuration , we see that aluminium can attain stability by losing 3 electrons from outer shell.
after losing 3 electrons , the ion formed is given as Al³⁺
hence the correct options to fill in the blanks are lose and Al³⁺
