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3 years ago

Data which statement best describes sound

Chemistry

1 answer:

enyata [817]3 years ago

7 0

Answer:

Sound is a form of energy that transmits in form of longitudinal waves, and are interpreted as pulses by the brain into useful action.

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Balance in basic solution: O2(g) + Cr³+ (aq) → H₂O2 (1) + Cr₂O7²- (aq)

likoan [24]

cr2o72+H2o2-(r3+o2)

Explanation:

r62o72+H2o2-(r3+o2)

3 0

3 years ago

What are two conditions atoms must have in order to form covalent bonds with one another?

bulgar [2K]

Both atoms must be non-metals,
Both atoms must have an incomplete outer energy level / shell of electrons

6 0

4 years ago

3) A saturated solution of PbCl2 in water was prepared and filtered. From the filtrate (solution collected after filtration), 50

qaws [65]

Answer: a) 0.0144mol/L

b) $1.19\times 10^{-5}$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

The equation for the ionization of the $PbCl_2$ is given as:

We are given:

Solubility of $PbCl_2$ = $\frac{2.0g}{0.5L}=4g/L$

Molar Solubility of $PbCl_2$ = $\frac{4g/L}{278.1g/mol}=0.0144mol/L$

1 mole of $PbCl_2$ gives 1 mole of $Pb^{2+}$ and 2 moles of $Cl^-$ ions

Solubility product of $PbCl_2$ = $[Pb^{2+}][Cl^-]^2$

$K_{sp}=[0.0144][2\times 0.0144]^2$

$K_{sp}=1.19\times 10^{-5}$

Thus the solubility product constant is $1.19\times 10^{-5}$

4 0

3 years ago

If 5750 Joules of energy are added to 455 grams of granite at 24.0 C, what is the final temperature of the granite The specific

Darina [25.2K]

Joules/ (Grams * Kelvin)
Kelvin = Celsius + 273.15

5 0

3 years ago

An ideal diatomic gas starting at room temperature T1 = 300 K and atmospheric pressure p1 = 1.0 atm is compressed adiabatically

tangare [24]

Answer:

The final temperature of the given ideal diatomic gas: T₂ = 753.6 K

Explanation:

Given: Atmospheric pressure: P = 1.0 atm

Initial Volume: V₁ , Final Volume: V₂ = V₁ (1/10)

⇒ V₁ / V₂ = 10

Initial Temperature: T₁ = 300 K, Final temperature: T₂ = ? K

For a diatomic ideal gas: γ = 7/5

For an adiabatic process:

$V^{\gamma-1 }T = constant$

$V_{1}^{\gamma-1 }T_{1} = V_{2}^{\gamma-1 }T_{2}$

$\left [\frac{V_{1}}{V_{2}} \right ]^{\gamma-1 } = \frac{T_{2}}{T_{1}}$

$\left [10 \right ]^{\frac{7}{5}-1 } = \frac{T_{2}}{300 K}$

$\left [10 \right ]^{\frac{2}{5} } = \frac{T_{2}}{300 K}$

$2.512 = \frac{T_{2}}{300 K}$

$T_{2} = 753.6 K$

Therefore, the final temperature of the given ideal diatomic gas: T₂ = 753.6 K

8 0

3 years ago