We will see that f'(x) > 0, which means that f(x) is an increasing function.
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How to prove that the function is increasing?</h3>
For any function f(x), if f'(x) > 0, then f(x) is increasing for any value of x.
Here we have the cubic function:
f(x) = x³ + 4x
If we differentiate this, we get:
f'(x) = df(x)/dx = 3x² + 4.
And notice that x² is always positive, then f'(x) > 0, which means that f(x) is an increasing function.
If you want to learn more about cubic functions:
brainly.com/question/20896994
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Answer: Hello There!!
w = -5/2
Step-by-step explanation:
4(w+1)=−6
Step 1: Simplify both sides of the equation.
4(w+1)=−6
(4)(w)+(4)(1)=−6(Distribute)
4w+4=−6
Step 2: Subtract 4 from both sides.
4w+4−4=−6−4
4w=−10
Step 3: Divide both sides by 4.
4w/4 = -10/4
Answer:
52.2
Step-by-step explanation:
Answer:
Step-by-step explanation:
