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atroni [7]
3 years ago
14

The net force acting on a Cessna 172 airplane has a magnitude of 1900 N and points in the positive x direction. If the plane has

a mass of 860 kg, what is its acceleration?
Physics
1 answer:
Kay [80]3 years ago
4 0

Answer: 10.05m/s²

Explanation:

Force acting on the plane has a magnitude of 1900N.

Mass of plane = 860kg

We then calculate the acceleration which will be:

= 1900 / 860

= 2.21 m/s²

Since acceleration due to gravity is equal to 9.8m/s², then the net acceleration will be:

= ✓(2.21² + 9.8²)

= ✓(4.88 + 96.04)

=✓100.92

= 10.05m/s²

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A ball is launched with initial speed v from ground level up a frictionless slope (This means the ball slides up the slope witho
amid [387]

Answer:

hmax = 1/2 · v²/g

Explanation:

Hi there!

Due to the conservation of energy and since there is no dissipative force (like friction) all the kinetic energy (KE) of the ball has to be converted into gravitational potential energy (PE) when the ball comes to stop.

KE = PE

Where KE is the initial kinetic energy and PE is the final potential energy.

The kinetic energy of the ball is calculated as follows:

KE = 1/2 · m · v²

Where:

m = mass of the ball

v = velocity.

The potential energy is calculated as follows:

PE = m · g · h

Where:

m = mass of the ball.

g = acceleration due to gravity (known value: 9.81 m/s²).

h = height.

At  the maximum height, the potential energy is equal to the initial kinetic energy because the energy is conserved, i.e, all the kinetic energy was converted into potential energy (there was no energy dissipation as heat because there was no friction). Then:

PE = KE

m · g · hmax = 1/2 · m · v²

Solving  for hmax:

hmax = 1/2 · v² / g

4 0
4 years ago
A proposed space station consists of a circular tube that will rotate about its center (like a tubular bicycle tire), Fig. 5–39.
Trava [24]

Answer:

1742.24106 revolutions per day

Explanation:

v = Velocity

d = Diameter = 1.1 km

r = Radius = \dfrac{d}{2}=\dfrac{1.1}{2}=0.55\ km

g = Acceleration due to gravity = 9.81 m/s²

g = 0.9 g

The centrifugal force will balance the gravitational force

F_c=mg\\\Rightarrow \dfrac{mv^2}{r}=m0.9g\\\Rightarrow v=\sqrt{\dfrac{0.9gmr}{m}}\\\Rightarrow v=\sqrt{0.9gr}\\\Rightarrow v=\sqrt{0.9\times 9.81\times 0.55\times 10^3}\\\Rightarrow v=69.68464\ m/s

\dfrac{1}{T}=\dfrac{v}{2\pi r}\\\Rightarrow \dfrac{1}{T}=\dfrac{69.68464}{2\pi 0.55\times 10^3}\times 24\times 60\times 60\\\Rightarrow \dfrac{1}{T}=1742.24106\ rev/day

The rotation speed is 1742.24106 revolutions per day

6 0
3 years ago
Read 2 more answers
When a satellite is a distance R from the center of the Earth, the force of gravity on the satellite is F. What is the gravitati
Lubov Fominskaja [6]

Gravitational force on a satellite is given by the formula

F = \frac{GMm}{r^2}

now here we know that force on the satellite is F when its distance from center of Earth is R

Now the distance from the center of earth will be 3R so the force is given as

F' = \frac{GMm}{(3R)^2}

F' = \frac{GMm}{9R^2}

so if we compare it with initial value of force then it is

F' = \frac{F}{9}

so correct answer is

(1) F/9

7 0
3 years ago
Read 2 more answers
T = mg + ma solve for a
Gnoma [55]
You said                        T           =  mg + ma

Subtract  mg 
from each side:            T - mg  =            ma

Divide each side by  m :      a  =  (T-mg) / m

                                          or  a  =  T/m  -  g
5 0
4 years ago
Sara pushes her 45 kg younger sister with a force of 300 N to the right and encounters 120 N of friction. Calculate the little s
Karo-lina-s [1.5K]
The Net force is 280 N (300-120). The acceleration = force / mass = 280 / 45 = 6.2 m/s^2
8 0
3 years ago
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