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noname [10]
3 years ago
9

The cells of multicellular organisms, like you and me, become specialized for particular tasks and communicate with one another

to maintain homeostasis. Cells, tissues and organs all help to maintain the organism's internal environment. But what about a unicellular organism? Does it maintain homeostasis? If yes, what part of the cell plays a part in this process? A) Yes, the DNA directs what happens inside the cell at all times. B) No. Because these cells live in water, internal balance is automatic. C) Yes, the cell membrane along with the nucleus helps maintain internal balance. D) No. Internal balance in unicellular organisms is based on osmosis of water into and out of the cell.
Chemistry
1 answer:
iVinArrow [24]3 years ago
3 0

D) No. Internal balance in unicellular organisms is based on osmosis of water into and out of the cell.

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For an assignment, Alexis has to write a scientific question. She writes, "How much money should be spent to research brain canc
Andru [333]

Answer:

D will brain cancer eventually be curable?

Explanation:

3 0
4 years ago
Walter gets a paper back in lab with “-2.75% error” written on it. He found the mass of an object to be 100.7 grams. What should
stepan [7]
0.0275x100.7= 2.8(approximately). 100.7-2.8=97.9grams
3 0
4 years ago
What is the molar mass of AlCl3
Julli [10]

Answer:

133.34 g/moles

Explanation:

but to make life easy it could be 133.4 g/ moles as well

7 0
3 years ago
The goose has a mass of 19.2 lb (pounds) and is flying at 7.10 miles/h (miles per hour). What is the kinetic energy of the goose
nata0808 [166]

Answer:

43.868 J

Explanation:

Kinetic energy of a body is the amount of energy possessed by a moving body. The SI unit of kinetic energy is the joule (kg⋅m²⋅s⁻²).

According to classical mechanics, kinetic energy = 1/2 m·v²

Where, m= mass in kg and v= velocity in m/s

Given: m = 19.2 lb and v = 7.10 miles/h

Since, 1 lb= 0.453592 kg

∴ m = 19.2 lb = 19.2 × 0.453592 kg = 8.709 kg

Also, 1 mi = 1609.34 m and 1 h = 3600 sec

∴ v = 7.10 mi/h = 7.10 × 1609.34 m ÷ 3600 sec = 3.174 m/sec

Therefore, <u>kinetic energy of the goose</u> = 1/2 m·v² = 1/2 × (8.709 kg)× (3.174 m/sec)² = 43.868 J

5 0
3 years ago
How many molecules are present in 4.21 moles of HBr?​
salantis [7]

Answer:

The answer is

<h3>2.53 × 10²⁴ molecules</h3>

Explanation:

The number of molecules present can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.21 × 6.02 × 10²³

We have the final answer as

<h3>2.53 × 10²⁴ molecules</h3>

Hope this helps you

6 0
3 years ago
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