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Vsevolod [243]
3 years ago
6

Convert 4.6 atm to mmHg.

Chemistry
1 answer:
Evgen [1.6K]3 years ago
3 0
It’s
3496 you can google this you know
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antimony has two naturally occuring isotopes, sb121sb121 and sb123sb123 . sb121sb121 has an atomic mass of 120.9038 u120.9038 u
Luda [366]

Considering the definition of atomic mass, isotopes and atomic mass of an element, sb121 has a percent natural abundance of 0.5726 or 57.26% and sb123 has a percent natural abundance of 0.4284 or 42.84%.

<h3>Definition of atomic mass</h3>

The atomic mass is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.

<h3>Definition of isotope</h3>

Isotopes are the chemical elements in which atomic numbers are the same, but the number of neutrons is different.

<h3>Definition of atomic mass</h3>

The atomic mass of an element is the weighted average mass of its natural isotopes.

This is, the atomic masses of elements are usually calculated as the weighted average of the masses of the different isotopes of each element, considering the relative abundance of each of them.

<h3>Percent natural abundance of each isotope</h3>

In this case, antimony has two naturally occuring isotopes, sb121 and sb123. You know:

  • sb121 has an atomic mass of 120.9038 u.
  • sb121 has a percent natural abundance of x.
  • sb123 has an atomic mass of 122.9042 u.
  • sb123 has a percent natural abundance of 1 -x (or, what is the same, the abundance is 100% - x%, since both isotopes form 100% of the element.)
  • Antimony has an average atomic mass of 121.7601 u

The average mass of antimony is expressed as:

121.7601 u= 120.9038 u x + 122.9042 u× (1 -x)

Solving:

121.7601 u= 120.9038 u x + 122.9042 u - 122.9042 u x

121.7601 u - 122.9042 u= 120.9038 u x - 122.9042 u x

(-1.1441 u)= (-2.0014) x

(-1.1441 u)÷ (-2.0014)= x

<u><em>0.5726= x or 57.26%</em></u>

So, 1 -x= 1- 0.5716 → <u><em>1-x= 0.4284 or 42.84%</em></u>

<u><em /></u>

Finally, sb121 has a percent natural abundance of 0.5726 or 57.26% and sb123 has a percent natural abundance of 0.4284 or 42.84%.

Learn more about average atomic mass:

brainly.com/question/4923781

brainly.com/question/1826476

brainly.com/question/15230683

brainly.com/question/7955048

#SPJ1

5 0
1 year ago
A second cross was done using a different pair of mice.One parent was a mouse with white fur (bb).The was other parent was a mou
eimsori [14]
Bb, or mostly dominant with a little recessive
3 0
2 years ago
 ** GIVEN THE BRAINLIEST** IF CORRECT!!
Drupady [299]

Answer is: The zooplankton can be used to help control algal growth in some coral communities.

Hypothesis is a suggested explanation for an observable phenomenon.

Steps of the scientific method:  

1) ask a question about something that is observed.

2) do background research.

3) construct a hypothesis, an attempt to answer questions with an explanation that can be tested.  In this example, does the presence of a certain type of zooplankton inhibited the algae growth

4) test of hypothesis.  

5) analyze collected data and draw a conclusion.  In this example, the zooplankton can be used to help control algal growth.

5 0
3 years ago
What is the density of carbon dioxide gas at -25.2°C and 98.0 kPa? A. 0.232 g/L OB. 0.279 g/L OC. 0.994 g/L OD. 1.74 g/L O E. 2.
Black_prince [1.1K]

Answer:

E. 2.09\frac{g}{L}

Explanation:

From the ideal gasses equation we have:

PV=nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

The number of moles is also expressed as: n=\frac{mass}{Molar mass}

If replacing this in the ideal gasses equation we have:

PV=\frac{mass}{Molarmass}.RT

If we pass V to divide, we have:

P=\frac{mass}{V}.\frac{RT}{Molarmass}

And the density d = \frac{mass}{V}, so replacing, we have:

P=\frac{dRT}{M}

Solving for d, we have:

d=\frac{P.M}{R.T}

Now we have to be sure that we have the correct units, so we need to convert the units for pressure and temperature:

-Convert P=98kPa to atm

98.0kPa*\frac{0.00986923atm}{1kPa}=0.97atm

-Convert T=-25.2°C to K

-25.2^{o}C+273.15=247.95K

Finally we can replace the values in the equation:

d=\frac{(0.97atm)*(44.01\frac{g}{mol})}{(0.082\frac{atm.L}{mol.K})*(247.15K)}

d=2.09\frac{g}{L}

8 0
3 years ago
Which value is most likely to be the pH of a salt that is formed by the reaction of a strong acid and a weak base?
trapecia [35]
7.0 is the answer I think
6 0
2 years ago
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