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kirill [66]
2 years ago
10

Consider a 180. g sample of water. The specific heat of water is 1.00 cal(g · °C) or 4.18 J/(g: °0).

Chemistry
1 answer:
ludmilkaskok [199]2 years ago
3 0

Answer:

Explanation:

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Question

Consider a 180. g sample of water. The specific heat of water is 1.00 cal(g · °C) or 4.18 J/(g: °0).

(a) How much energy, in calories, is released as the water is cooled from 55.0°C to 12.0°C? (Enter your

answer in scientific notation.)

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Answer:

Data is not valid

Explanation:

When two liquids having different temperatures are mixed, regardless of the volumes, the final mix temperature will ALWAYS be between the initial temperature values.

1st Law Thermo => Law of Conservation of Energy => Energy can not be created nor destroyed, only changed in form. Mixing 22°C with 75°C will NOT result in a mix having a final temperature of 80°C.

∑ΔE = 0 => (mcΔT)₁ + (mcΔT)₂ = 0

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