Explanation:
It is given that,
Mass of the man, m = 68 kg
Terminal velocity of the man, v = 59 m/s
We need to find the rate at which the internal energy of the man and of the air around him increase. The gravitational potential energy of the man is given by :
Differentiating equation (1) wrt t as :
Since,
So, the internal energy of the man and the air around him is increasing at the rate of 39317.6 J/s. Hence, this is the required solution.
The last paragraph is the correct statement. Please don't make me type it all out.
The correct answer is: (A) An Atmosphere
Explanation:
The atmosphere of Venus is almost ninety times denser than that of Earth. Due to Venus' denser atmosphere and chemical composition (as its atmosphere comprises of over 96% of Carbon dioxide), it experience an immense greenhouse effect. That is why its surface temperature remains higher than 470°. At that very high temperature, it is impossible to have life on the surface of Venus.
Answer:
The electrons in oxygen are paired while in nitrogen, they are not.
Explanation:
To analyse this we start with writing out the ground state electronic configurations for both elements.
Oxygen: 1s²2s²2p4 meaning the p subshell has the following arrangement of electrons ↑↓ ↑ ↑
Nitrogen : 1s²2s²2p³ meaning the p subshell has the following arrangement of electrons ↑ ↑ ↑
Clearly the paired electron in oxygen will be experiencing repulsion from the electron it shares an orbital with causing it to be removed easily. The electrons in nitrogen are unpaired, each orbital is singly occupied
The temperature inside the copper rod varies linearly with the distance from the hot end of the rod. This means that we can find the temperature at 23 cm (let's call it 'point A') from the cool end by solving a linear proportion.
The temperature difference between the two ends of the rod is
and this corresponds to a length of 81 cm. Therefore, we can write:
from which we find
This is not the final answer actually; this is the temperature difference between the cool end and point A. So, the temperature at point A is