It makes no sense how you typed this problem out.
The answer in (B)214.4J
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If the transformer’s primary coil has 20 times as many turns of wire in it as the secondary coil has, then the secondary coil provides a small voltage rise for the large amount of current that flows through it.
Answer: Option B
<u>Explanation:</u>
A transformer has a two types of coils, the first one is primary coils and the second one is secondary coil. A secondary coils with hardly any turns in it provides the charges going through it just limited quantities of energy.
Without a long separation over which to do chip away at the charges streaming in the loop, the transformer delivers just a little ascent in the voltage of those charges. Be that as it may, the coil can give this little voltage to ascend to a huge current without requiring an excess of power supply from the input circuit.
The proton will be moving if it is to follow a circular path with radius 2cm in magnetic field of 0.7T is 1.34 x 10⁷ m/s.
<h3>What is magnetic field?</h3>
It is the region of space where a charge experiences the magnetic force when it enters the field.
While moving in the circular path, centripetal force is equal to the magnetic force.
Fm = Fc
q x v x B = m x v² / r
v= qBr /m
where mass of proton m =1.67262 × 10−27 kg, charge of proton q =1.6 x 10⁻¹⁹ C and magnetic field B =0.7T.
Then, velocity is
v = 1.6 x 10⁻¹⁹ x 0.7 x 0.02 / 1.67262 × 10⁻²⁷
v = 1.34 x 10⁷ m/s.
Thus, the proton will be moving if it is to follow a circular path with radius 2cm in magnetic field of 0.7T is 1.34 x 10⁷ m/s.
Learn more about magnetic field.
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