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Zina [86]
3 years ago
8

Imagine you are on an airplane. Your plane has flown from 30 degrees North to 42 degrees North. How far have you flown?

Physics
1 answer:
ycow [4]3 years ago
7 0
The answer to your question is 12 degrees because you subtract 42 degrees minus 30 degrees to get 12 degrees
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what is it called when a soccer ball accelerates faster than a bowling ball when the same amount of force is applied?
STatiana [176]

Answer:

Answer: 2nd Law - The soccer ball weighs less than the bowling ball, so you need less force to get it to have the same acceleration as the bowling ball.

Explanation:

7 0
2 years ago
A wall, acted upon by a force of 20 N, does not move. The work done on the wall in this process is
prisoha [69]

0J

Explanation:

A wall that is acted upon by a force of 20N does not move suggests that no work has been done on the wall.

Work done is the force applied to move in the direction of the applied force.

   Work done = force x distance.

Since the distance is 0, the work done on the body too is zero.

Work is only done when forces moves a body through a given distance.

Learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

5 0
3 years ago
Someone got this paper?
Snezhnost [94]
First question (upper left):
1/Req = 1/12 + 1/24 = 1/8
Req = 8 ohms
Voltage is equal through different resistors, and V1 = V2 = 24 V.
Current varies through parallel resistors: I1 = V1/R1 = 24/12 = 2 A. I2 = 24/24 = 1 A.

Second question (middle left):
V1 = V2 = 6 V (parallel circuits)
I1 = 2 A, I2 = 1 A, IT = 2+1 = 3 A.
R1 = V1/I1 = 6/2 = 3 ohms, R2 = 6/1 = 6 ohms, 1/Req = 1/2 + 1/1, Req = 2/3 ohms

Third question (bottom left):
V1 = V2 = 12 V
IT = 3 A, meaning Req = V/It = 12 V/3 A = 4 ohms
1/Req = 1/R1 + 1/R2, 1/4 = 1/12 + 1/R2, R2 = 6 ohms
I1 = V/R1 = 1 A, I2 = V/R2 = 2 A

Fourth question (top right):
1/Req = 1/20 + 1/20, Req = 10 ohms
IT = 4 A, so VT = IT(Req) = 4*10 = 40 V
Parallel circuits, so V1 = V2 = VT = 40 V
Since the resistors are identical, the current is split evenly between both: I1 = I2 = IT/2 = 2 A.

Fifth question (middle right):
1/Req = 1/5 + 1/20 + 1/4, Req = 2 ohms
IT = VT/Req = 40 V/2 ohms = 20 A
V1 = V2 = V3 = 40 V
The current of 20 A will be divided proportionally according to the resistances of 5, 20, and 4, the factors will be 5/(5+20+4), 20/(5+20+4), and 4/(5+20+4), which are 5/29, 20/29, and 4/29.
I1 = 20(5/29) = 100/29 A
I2 = 20(20/29) = 400/29 A
I3 = 20(4/29) = 80/29 A

Sixth question (bottom right):
V2 = 30V is given, but since these are parallel circuits, V1 = VT = 30 V.
Then I1 = V1/R1 = 30 V/10 ohms = 3 A.
I2 = 30 V/15 ohms = 2 A.
IT = 3 + 2 = 5 A
1/Req = 1/10 + 1/15, Req = 6 ohms
6 0
3 years ago
What constant acceleration, in SI units, must a car have to go from zero to 60 mph in 10 s? How far has the car traveled when it
nalin [4]

Answer:

Explanation:

initial velocity, u = 0

final velocity, v = 60 mph = 26.8 m/s

time t = 10 s

Let a be the acceleration and s be he distance traveled.

Use first equation of motion

v = u + a t

26.8 = 0 +  a x 10

a = 2.68 m/s

Use second equation of motion

s = ut + 1/2 at²

s = 0 + 0.5 x 2.68 x 10 x 10

s = 134 m

As, 1 m = 3.28 ft

So, s = 134 x 3.28 ft

s = 439.6 ft

7 0
3 years ago
Determine W (or fuel energy) required to launch a satellite of mass m at rest from a launching pad placed at the surface earth,
jeka57 [31]

Answer:

5. 9GmM/(10R)

Explanation:

m is the mass of the satellite

M is the mass of the earth

W is the energy required to launch the satellite

Energy at earth surface = Potential energy (PE) + W

W = Energy at earth surface - Potential energy (PE)

But PE = -\frac{GMm}{R}

Therefore: W = Energy at earth surface - \frac{GMm}{R}

Energy at earth surface (E) at an altitude of 5R = -\frac{GMm}{5r} +\frac{1}{2}mV^2

But V=\sqrt{\frac{GM}{5R} }

Therefore: E=-\frac{GMm}{5R}+\frac{1}{2}m(\sqrt{\frac{GM}{5R} } )^2=  -\frac{GMm}{5R}+\frac{GMm}{10R}  = -\frac{GMm}{10R}

W = E - PE

W=-\frac{GMm}{10R}-(-\frac{GMm}{R})=-\frac{GMm}{10R}+\frac{GMm}{R}=\frac{9GMm}{10R} \\W=\frac{9GMm}{10R}

7 0
3 years ago
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