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Nataly [62]
3 years ago
8

The HCF of smallest 2 digit composite number and smallest 3 digit prime number is​

Mathematics
1 answer:
malfutka [58]3 years ago
8 0
HCF of smallest 2 digit composite number and 3 digit prime number is 2
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13-6x=(2x-5)^2+3 what answer
svet-max [94.6K]
<span><span>13−<span>6x</span></span>=<span><span><span>(<span><span>2x</span>−5</span>)</span>2</span>+3</span></span>Step 1: Simplify both sides of the equation.<span><span><span>−<span>6x</span></span>+13</span>=<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span></span>Step 2: Subtract 4x^2-20x+28 from both sides.<span><span><span><span>−<span>6x</span></span>+13</span>−<span>(<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>)</span></span>=<span><span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>−<span>(<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>)</span></span></span><span><span><span><span>−<span>4<span>x2</span></span></span>+<span>14x</span></span>−15</span>=0</span>Step 3: Use quadratic formula with a=-4, b=14, c=-15.<span>x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>x=<span><span><span>−<span>(14)</span></span>±<span>√<span><span><span>(14)</span>2</span>−<span><span>4<span>(<span>−4</span>)</span></span><span>(<span>−15</span>)</span></span></span></span></span><span>2<span>(<span>−4</span>)</span></span></span></span><span>x=<span><span><span>−14</span>±<span>√<span>−44</span></span></span><span>−<span>8</span></span></span></span>
5 0
3 years ago
PLEASE SHOW ALL YOUR WORK TO GET BRAINLIEST AWARD
krek1111 [17]
<span> 7x+2y=5;13x+14y=-1 </span>Solution :<span><span> {x,y} = {1,-1}</span>  </span>System of Linear Equations entered :<span><span>  [1] 7x + 2y = 5 </span><span>  [2] 13x + 14y = -1 </span></span>Graphic Representation of the Equations :<span> 2y + 7x = 5 14y + 13x = -1 </span>Solve by Substitution :

// Solve equation [2] for the variable  y  
 

<span> [2] 14y = -13x - 1 [2] y = -13x/14 - 1/14</span>

// Plug this in for variable  y  in equation [1]

<span><span>  [1] 7x + 2•(-13x/14-1/14) = 5 </span><span>  [1] 36x/7 = 36/7 </span><span>  [1] 36x = 36 </span></span>

// Solve equation [1] for the variable  x  

<span><span>  [1] 36x = 36</span>  <span>  [1] x = 1</span> </span>

// By now we know this much :

<span><span>  x = 1</span> <span>  y = -13x/14-1/14</span></span>

<span>// Use the  x  value to solve for  y  
</span>

<span>   y = -(13/14)(1)-1/14 = -1 </span>Solution :<span><span> {x,y} = {1,-1}</span>  <span> Processing ends successfully</span></span>
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