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Ugo [173]
3 years ago
10

Why is dissolving important??

Chemistry
1 answer:
Irina18 [472]3 years ago
4 0

Water is called the "universal solvent" because it is capable of dissolving more substances than any other liquid. This is important to every living thing on earth. It means that wherever water goes, either through the air, the ground, or through our bodies, it takes along valuable chemicals, minerals, and nutrients.

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Ytu perform an electrolysis reaction using FeCl, iron (1) chloride. Which of the following will happen?
FrozenT [24]

Answer:

The answer is "Option B"

Explanation:

when we react with FeCl, iron, and chloride to both the electrolysis. So, iron is charged positive ion, as well as passes to the negative, is cathode electrode. But there is a decrease in the cathode.

The equation can be defined as follows:

FeCl_2 \longrightarrowFe + Cl_2

In the above equation, when the iron chloride electrolysis solution, it will give the iron(II) and the chlorine. This process happens when the hydrogen chloride solution at a temperature of about 90 ° C.

5 0
4 years ago
The polyatomic ion with the formula CN- is called
Zinaida [17]

The correct answer is cyanate.

The polyatomic ion with the formula CN⁻ is called cyanate. A polyatomic ion has two or more atoms bonded together.

CN⁻ contains the cyano functional group wherein a carbon atom forms a triple-bond to a nitrogen atom. CN⁻ is a polyatomic anion that is present in inorganic compounds.


4 0
3 years ago
Read 2 more answers
In a reduction half-reaction, which amount is shown?
eduard
ODghe number of electrons needed balance
4 0
3 years ago
QUESTION 3 Consider a solution containing 0.80 M NaF and 0.80 M HF. Calculate the moles of HF and the concentration of HF after
Lisa [10]

Answer:

0.056moles HF and 0.70M

Explanation:

When a strong acid is added to a buffer, the acid reacts with the conjugate base.

In the system, NaF and HF, weak acid is HF and conjugate base is NaF. The reaction of NaF with HCl (Strong acid) is:

NaF + HCl → HF + NaCl

Initial moles of NaF and HF in 60.0mL of solution are:

NaF:

0.0600L × (0.80mol / L)= 0.048 moles NaF

HF:

0.0600L × (0.80mol / L)= 0.048 moles HF

Then, the added moles of HCl are:

0.0200L × (0.40mol / L) = 0.008 moles HCl.

Thus, after the reaction, moles of HF produced are 0.008 moles + the initial 0.048moles of HF, moles of HF are:

<em>0.056moles HF</em>

<em></em>

In 20.0mL + 60.0mL = 80.0mL = 0.0800L, molarity of HF is:

0.056mol HF / 0.0800L = <em>0.70M</em>

6 0
3 years ago
Question has to do with chemistry and is in the picture.
Fittoniya [83]

Answer:

the answer is 69

Explanation:

hope this helps

have an awesome day -TJ

8 0
2 years ago
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