1) Balance of mass
CxHyOz + O2 ---> CO2 + H20
0.880 g + X = 1.760g + 0.720 g
=> X = 1.760g + 0.720g - 0.880g = 1.6 g of O2
2) C in CO2:
molar mass of CO2 = 44 g/mol
=> 12 g C / 44 g CO2 * 1.760 g CO2 = 0.480 g C
3) H in H2O
molar mass of H2O = 18.0 g/mol
2 g H / 18.0 g H2O * 0.720 g H2O = 0.080 g H
4) O
4a) O in CO2: 32gO / 44 g CO2 * 1.760 g CO2 = 1.280 g O
4b) O in H2O: 16gO / 18 gH2O * 0.720 g H2O = 0.640 g O
4c) O in CxHyOz = 1.280 g + 0.64 g - 1.6 g = 0.320 g O
5) Convert grams into moles
C: 0.480 g / 12 g/mol = 0.04 mol
H: 0.08 g / 1 g/mol = 0.08 mol
O: 0.32 g / 16 g/mol = 0.02 mol
6) Divide by the smallest number
C: 0.04 / 0.02 = 2
H: 0.08 / 0.02 = 4
O: 0.02 / 0.02 = 1
7) Use those numbers as subscripts for the empirical formula:
C2 H4 O
Answer: C2H4O
Answer:
No. Au⁺ has a complete 5d sublevel.
Explanation:
The color of the transition metal/ion arises due to d-d transition which means that when energy of certain frequency is passed though the solution of the transition metal ions, the electrons of the d orbital gain some energy and goes to higher energy level. The energy absorbed lies in the visible region and thus they are appeared colored.
The electronic configuration of Au is:
1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰5s²5p⁶4f¹⁴5d¹⁰6s¹
If the gold atom looses one electron, then the electronic configuration is:
1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰5s²5p⁶4f¹⁴5d¹⁰
<u>Hence, in the configuration, the 5d orbital is full filled and there is no scope for d-d transition. </u>
<u>Thus, there will Au⁺ will not be colored.</u>
Low pressure and high temperature will make real gasses behave like ideal gasses.
The answer I believe would be A