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Pani-rosa [81]
3 years ago
13

Martin slowly pours an unknown liquid into a container that originally had some water in it. He is measuring the temperature in

the container as he does this.
The temperature in the container rises very fast.


What kind of change is likely to be happening in the container?
A chemical change.

A physical change.

Both a chemical and a physical change.

Neither a chemical nor a physical change.
Chemistry
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

A chemical change.

Explanation:

As the temperature rises fast, the kind of change that can be said to be occurring is a chemical change.

One of the way to know of a chemical change is occurring is that new kinds of  matter is formed and also, there is either an evolution or absorption of heat energy in the process.

Since heat is liberated in this change, an exothermic chemical reaction is taking place.

So this is a chemical change.

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If 852.04 g Al(NO3)3 reacted with the 741.93 g Na2CO3, which would be the limiting reagent?
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Answer:

Al(NO3)3

Explanation:

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How many protons and electrons are in Hg+
Gala2k [10]

Answer:

There are 80 protons and 80 electrons in Hg+ (Mercury)

Explanation:

Name Mercury

Symbol Hg

Atomic Number 80

Atomic Mass 200.59 atomic mass units

Number of Protons 80

Number of Neutrons 121

Number of Electrons 80

Melting Point -38.87° C

Boiling Point 356.58° C

Density 13.456 grams per cubic centimeter

Normal Phase Liquid

Family Transitions Metals

Period Number 6

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Words that mean the same thing<br> decrease,<br> diminish,<br> dwindle
strojnjashka [21]

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Subside

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7 0
3 years ago
Read 2 more answers
A pure sample of a new chemical compound was analyzed and was found to have the following mass percentages: Al 31.5 %; O 56.1 %;
rjkz [21]

Answer:

The answer to your question is empirical formula   Al₃O₉S

Explanation:

Data

Al = 31.5 %

O = 56.1 %

S = 12.4 %

Process

1.- Look for the atomic masses of the elements

Al = 27 g

O = 16

S = 32

2.- Represent the percentages as grams

Al = 31.5 g

O = 56.1 g

S = 12.4 g

3.- Convert these masses to moles

                               27 g of Al ----------------- 1 mol

                               31.5 g ----------------------  x

                                x = 1.17 moles

                               16 g of O ----------------  1 mol

                               56.1 g of O -------------  x

                                  x = 3.5 mol

                               32 g of S ---------------  1 mol

                               12.4 g of S -------------   x

                                x = 0.39 moles

4.- Divide by the lowest number of moles

Al =   1.17 / 0.39  = 3

O =    3.5 / 0.39 = 8.9 ≈ 9

S  =   0.39 / 0.39 = 1

5.- Write the empirical equation

                                Al₃O₉S

4 0
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Plsss help <br> will mark BRAINLIEST
satela [25.4K]

Answer:

c

Explanation: just a chemachal

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