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Pani-rosa [81]
3 years ago
13

Martin slowly pours an unknown liquid into a container that originally had some water in it. He is measuring the temperature in

the container as he does this.
The temperature in the container rises very fast.


What kind of change is likely to be happening in the container?
A chemical change.

A physical change.

Both a chemical and a physical change.

Neither a chemical nor a physical change.
Chemistry
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

A chemical change.

Explanation:

As the temperature rises fast, the kind of change that can be said to be occurring is a chemical change.

One of the way to know of a chemical change is occurring is that new kinds of  matter is formed and also, there is either an evolution or absorption of heat energy in the process.

Since heat is liberated in this change, an exothermic chemical reaction is taking place.

So this is a chemical change.

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A substance made of one or more atoms of a single type is a/an
Mkey [24]
I think the answer is a molecule
5 0
3 years ago
Explain the Law of Conservation of Mass in terms of the atoms and bonds in a chemical reaction.
nasty-shy [4]

Answer:

no matter is destroyed or created, it merely changes form. In terms of atoms and bonds, there will be the same amount of atoms at the beginning of an experiment as the amount of atoms at the end of experiment. All that will have happened, is that during the reaction, bonds will have been broken and formed making new compounds. However, the amount of atoms remains exactly the same because matter can not be created or destroyed

Hope this helps!

8 0
3 years ago
A sample of nitrogen gas has a volume of 578 mL and a pressure of 124.1 kPa. What volume would the gas occupy at 80.2 kPa if the
Nataly_w [17]

Answer:

V2 = 894.4mL

Explanation:

P1= 124.1, V1= 578mL, P2 = 80.2kPa, V2= ?

Applying Boyle's law

P1V1 = P2V2

Substitute and simplify

124.1*578=80.2*V2

V2= 894.4mL

4 0
3 years ago
When an electron in an atom moves from a higher, less stable level, down to a lower, more stable level, a photon is
Wittaler [7]

Answer:

Emitted

Explanation:

8 0
3 years ago
Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(
kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

4 0
3 years ago
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