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Pani-rosa [81]
3 years ago
13

Martin slowly pours an unknown liquid into a container that originally had some water in it. He is measuring the temperature in

the container as he does this.
The temperature in the container rises very fast.


What kind of change is likely to be happening in the container?
A chemical change.

A physical change.

Both a chemical and a physical change.

Neither a chemical nor a physical change.
Chemistry
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

A chemical change.

Explanation:

As the temperature rises fast, the kind of change that can be said to be occurring is a chemical change.

One of the way to know of a chemical change is occurring is that new kinds of  matter is formed and also, there is either an evolution or absorption of heat energy in the process.

Since heat is liberated in this change, an exothermic chemical reaction is taking place.

So this is a chemical change.

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CaHeK987 [17]
Warmer atoms expand. There is also more movement. This is also explained when putting it into terms with solid vs. gas. In a solid, the atoms vibrate, but they can't move very far because there is not a lot of space between them. In a gas, on the other hand, the atoms are spread apart, and they move very fast. Putting it into context with water, the steam (gas) version is hot, and the ice cube (solid) version is cold. Which one moves more freely? The gas.
4 0
4 years ago
28.
OlgaM077 [116]

Answer:

i don't know

Explanation:

4 0
2 years ago
What is the molarity of a solution prepared by diluting 250 mL of a 40% H2SO4 solution to 1 Liter? The density of the stock solu
kiruha [24]

Answer:

1.195 M.

Explanation:

  • We can calculate the concentration of the stock solution using the relation:

<em>M = (10Pd)/(molar mass).</em>

Where, M is the molarity of H₂SO₄.

P is the percent of H₂SO₄ (P = 40%).

d is the density of H₂SO₄ (d = 1.17 g/mL).

molar mass of H₂SO₄ = 98 g/mol.

∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.

  • We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.

<em>∴ (MV) before dilution = (MV) after dilution</em>

M before dilution = 4.78 M, V before dilution = 250 mL.

M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.

∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.

3 0
3 years ago
________ investigations allow for the control of variables
zlopas [31]

An experimental investigation allows you to control the variables.

Explanation:

Experimental investigations include a method in which a "fair test" is created and variables are actively planned, managed, and measured in an attempt to gather testimony to confirm or negate a causal relationship. Experimental investigations have a control group which does not accept any treatment.

3 0
4 years ago
Read 2 more answers
Are the atoms conserved during a chemical change even though new molecules are made?
Alex
The best answer would be yes because some of the old ones will give a "boost" to the new ones that come in. Hope this helped!
3 0
4 years ago
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