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Nataly [62]
2 years ago
13

Using the following equation, 2C2H6 +7O2 -->4CO2 +6H2O, if 2.5g C2H6 react with 170g of O2, how many grams of water will be p

roduced?
Chemistry
1 answer:
kirill [66]2 years ago
3 0

The mass of water (H₂O) that would be produced is 4.5 g

<h3>Stoichiometry </h3>

From the question, we are to determine the mass of water that would be produced.

From the given balanced chemical equation

2C₂H₆ +7O₂ → 4CO₂ +6H₂O

This means

2 moles of C₂H₆ reacts with 7 moles of O₂ to produce 4 moles of CO₂ and 6 moles of H₂O

Now, we will determine the number of moles of each reactant present

  • For Ethane (C₂H₆)

Mass = 2.5 g

Molar mass = 30.07 g

Using the formula,

Number\ of\ moles = \frac{Mass}{Molar\ mass}

Number of moles of C₂H₆ present = \frac{2.5}{30.07}

Number of moles of C₂H₆ present = 0.08314 mole

  • For Oxygen (O₂)

Mass = 170g

Molar mass = 31.999 g/mol

Number of moles of O₂ present = \frac{170}{31.999}

Number of moles of O₂ present = 5.3127 moles

Since

2 moles of C₂H₆ reacts with 7 moles of O₂

Then,

0.08314 mole of C₂H₆ will react with \frac{7 \times 0.08314 }{2}

 \frac{7 \times 0.08314 }{2} = 0.58198 mole

Therefore,

0.08314 mole of C₂H₆ reacts with 0.58198 mole of O₂ to produce 3 × 0.08314 moles of H₂O

3 × 0.08314 = 0.24942 mole

Thus, the number of moles of water (H₂O) produced is 0.24942 mole

Now, for the mass of water that would be produced,

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of water = 18.015 g/mol

Then,

Mass of water that would be produced = 0.24942 × 18.015

Mass of water that would be produced = 4.4933 g

Mass of water that would be produced ≅ 4.5 g

Hence, the mass of water (H₂O) that would be produced is 4.5 g

Learn more on Stoichiometry here: brainly.com/question/14271082

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Answer:

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

Isotopic notation:       Protons            Neutrons          Electrons

        ¹⁹⁷₇₉Au                  79                      118                    79

Solution:

p+n = atomic mass = 79+118 = 197

e = 79  (atomic number)               so the element with atomic number Au.

Isotopic notation:       Protons            Neutrons          Electrons

        ⁷⁹₃₅Br                    35                        44                    35

Solution:

Number of neutrons = atomic mass - number of protons=  79-35 = 44

Number of protons and electrons are equal so number of electrons are 35.

Isotopic notation:       Protons            Neutrons          Electrons

        ¹²⁷₅₃I                          53                    74                      53

Solution:

The atomic number of iodine is 53.

Number of neutrons = atomic mass - number of protons= 127-53 = 74

Number of protons and electrons are equal so number of electrons are 53.

Isotopic notation:       Protons            Neutrons          Electrons

        ⁵⁶₂₆Fe                        26                       30                    26

Solution:

The atomic number of iron is 26.

atomic mass = n+p= 26+30= 56

Number of protons and electrons are equal so number of electrons are 26.

8 0
3 years ago
A mover packs books, CDs, and DVDs into a moving box. If the box contains 6.5 kg of books, 1.5 kg of CDs, and 2.0 kg of DVDs, wh
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Answer:

\text{Mass percentage}=\frac{\text{Mass of the substance}}{\text{Total mass}}\times 100

Given: Mass of books = 6.5 kg

Mass of CD's = 1.5 kg

Mass of DVD's = 2.0 kg

Total mass = 6.5 kg + 1.5 kg + 2.0 kg = 10 kg

\text {Mass percentage of books}=\frac{6.5kg}{10kg}\times {100}=65\%

\text {Mass percentage of CD's}=\frac{1.5kg}{10kg}\times {100}=15\%

\text {Mass percentage of DVD's}=\frac{2.0kg}{10}\times {100}=20\%

7 0
3 years ago
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