A two-slit Fraunhofer interference-diffraction pattern is observed with light of wavelength 672 nm. The slits have widths of 0.0

Question

3 years ago

14

3 mm and are separated by 0.24 mm. How many bright fringes will be seen inside the central diffraction maximum?

1 answer:

ololo11 [35] · Answer 1 · 2022-02-23T18:36:45+03:00

Answer:

Explanation:

In case of diffraction , angular width of central maxima =2 λ/d

λ is wave length of light and d is slit width

In case of interference , angular width of each fringe

= λ /D

D is distance between two slits

No of interference fringe in central diffraction fringe

=2 λ/d x D/λ = 2 x D /d = 2 x .24/.03 = 16.