use consevation of linear momentum
- m1v1+m2v2=(M1+M2)V3
- 281(2.82)+209(-1.72)=(209+281)V2
- 792.42-359.48=490v3
- 432.9=490v3
- V3=0.88m/s
Answer:
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Explanation:
Total force required = Mass x Acceleration,
F = ma
Here we need to consider the system as combine, total mass need to be considered.
Total mass, a = m₁+m₂+m₃ = 584 + 838 + 322 = 1744 kg
We need to accelerate the group of rocks from the road at 0.250 m/s²
That is acceleration, a = 0.250 m/s²
Force required, F = ma = 1744 x 0.25 = 436 N
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Answer:
letter C. The mass of the object.
Explanation:
i hope it helps.
I think it’s C. Marshmallow and toothpicks are used to show the composition of a water molecule
The answer is apparent weight is zero.
You are still accelerating downwards at 9.8m/s^2 (if you are on Earth).
You still are being affected by the Earth's gravity.
Not all because of the previous two statements.
Not none because apparent weight is zero as you are falling.
