Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
Answer:
Let the number to find be x
7 - 9x = 52
-9x = 52-7
- 9x = -45
Divide by - 9
x = 5
The number is 5
Hope this helps.
Answer:
Step-by-step explanation:
a. 5/2 ÷ 1/2 =
b. 6/9 ÷ 5/6
c. 3/6 ÷ 2/5
d. 7 1/2 ÷ 6
=
e. 1 1/3 ÷ 1 2/3=
- 4/3 ÷ 5/3 =
- 4/3 * 3/5 =
- 4/5
Answer:
c
Step-by-step explanation:
idk but im think im sure
Answer:
The answer would be 50
Step-by-step explanation: