All categories

2 years ago

1/5 (5x-15) -2x What is the question ?? How do I solve the problem ??

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

8 0

Answer:

$-x-3$

Step-by-step explanation:

They want you to simplify the expression.

Step 1: Apply the distributive property.

$\frac{1}{5} (5x)+\frac{1}{5} (-15-2x)$

Step 2: Cancel the common factor of 5.

$x+\frac{1}{5} (-15-2x)$

Step 3: Cancel the common factor of 5.

$x-3-2x$

Step 4: Subtract 2x from x.

$-x-3$

You might be interested in

A new car is purchased for $17,000 and over time its value depreciates by one half every 3 years. What is the value of the car 1

Jet001 [13]

Answer:

The answer is "$238".

Step-by-step explanation:

Current worth $= \$ 17,000$

depreciates by $\frac{1}{2}$ in 3 years.

time= 19 years

depreciates rate=?

Using formula:

$\to \text{Worth= Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}$

$\to A_t=A_0(1-\frac{r}{100})^t$

calculates depreciate value in 3 year $= \frac{1}{2} \times 17,000$

$= 8,500$

so,

$A_t=8,500\\\\A_0=17,000\\\\t=3\ years$

$\to A_t=A_0(1-\frac{r}{100})^t\\\\\to 8,500= 17,000(1-\frac{r}{100})^3\\\\\to \frac{8,500}{17,000}= (1-\frac{r}{100})^3\\\\\to \frac{1}{2}= (1-\frac{r}{100})^3\\\\\to (\frac{1}{2})^{\frac{1}{3}}= (1-\frac{r}{100})\\\\\to 0.793700526 = (1-\frac{r}{100})\\\\\to \frac{r}{100} = (1-0.793700526)\\\\\to \frac{r}{100} = (1-0.8)\\\\\to r= 0.2 \times 100 \\\\\to r= 20 \%$

depreciates rate= 20%

$\to \text{Worth= Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}$

$= \$ 17,000 (1- \frac{20}{100})^{19}\\\\= \$ 17,000 (1-0.2)^{19}\\\\= \$ 17,000 (0.8)^{19}\\\\= \$ 17,000 \times 0.014\\\\= \$ 238$

4 0

2 years ago

Read 2 more answers

Rewrite these in increasing order of length: 228 dm, 517 cm, 787 km, 4 m

vichka [17]

Answer: The correct order

8mm, 41 cm, 790 dm, 788m, 537 km

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

PLEAASE SOMEONE HELP ME IM SO STUCK finish the table using the equation y= x/2

BigorU [14]

First one is 0 second is 1 third is 2 and fourth is 3 hope it helps

7 0

1 year ago

How did business leaders in the late nineteenth century utilize vertical integration? a. They maintained control of the raw mate

bulgar [2K]

Business leaders in the late nineteenth century utilized vertical integration by maintaining control of production and distribution of their products.

Answer: Option C

Explanation:

Vertical integration is a competitive strategy that gives the company full control over one or more stages of product production or distribution. Rockefeller tirelessly tried to take full control of business 'oil refinery'. While other business people were flooding the area in search of quick fortune, Rockefeller was thinking of destroying his rivals and creating a real monopoly in the refining industry.

Looking for even more control, Rockefeller saw the benefits of organizing the transportation to his products. Then, he began to develop his business through vertical integration, in which the company analyses all aspects of the product life cycle, from raw material extraction, through the production process, to the final delivery of the product.

Other industrialists quickly followed, including Gustavus Swift, who at the end of the 19th century used vertical integration to dominate the American meat packaging industry.

3 0

2 years ago

John and Beth plan to visit a bookstore. Based on their previous visits to this bookstore, the probability distributions for the

lora16 [44]

Answer:

D) 0.1250

Step-by-step explanation:

Let P(J) = Probability of John to purchase 0 books

Let P(B) = Probability of Beth to purchase 0 books

P(J∩B) = Probability that both john and Beth will purchase 0 books .ie. a total of 0 books is purchased.

Since the decisions to purchase books are two independents events,

P(J∩B) = P(J) * P(B)

P(J) = 0.5

P(B) = 0.25

P(J∩B) = 0.5 * 0.25

P(J∩B) = 0.125

8 0

2 years ago