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saw5 [17]
3 years ago
11

In the expression 3x2y + 4x – 5x2y, are the terms 3x2y and –5x2y like terms? Explain by providing support for your answer.

Physics
2 answers:
lubasha [3.4K]3 years ago
6 0

Answer:

Yes, both terms are same.

Explanation:

The given expression is, 3x^2y+4x-5x^2y.

Let the first term, t_1=3x^2y

The second term, t_1=-5x^2y

Yes, the term 3x^2y\ and\ -5x^2y are like. As in both of these terms, the variables are same. Also, the exponent of the variables are same. These two terms can be added or subtracted.

As a result the given expression is equivalent to 4x-2x^2 y. Hence, this is the required solution.

Zanzabum3 years ago
3 0
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In which region of the periodic table do the elements NOT normally react chemically with other elements?
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We would say that it would be metals.

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3 years ago
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A small plane flies 40.0 km in a direction 60° north of east and then flies 30.0 km in a direction 15° north of east. Use the an
lana66690 [7]

Answer:

d= 64.7 km

\theta = 40.9^{o}

displacement vector=r_xi + r_yj =  48.9i + 42.4j

Explanation:

total distance = 40 + 30 = 70 km

during 1st flight

r_1 x = 40*cos60

r_1 x = 20 km

r_1 y = 40*sin60

r_1 y = 34.64 km

during 2nd flight

r_2 x = 30*cos15

r_2 x = 28.9 km

r_2 y = 30*sin15

r_2 y = 7.76 km

the two component of r are:

r_x = r_1x + r_2x = 20 + 28.9 = 48.9 km

r_y = r_1y + r_2y = 34.64 + 7.76 = 42.4 km

Geographical Direction \theta = tan^{-1}\frac{r_y}{r_x} [tex]\theta = 40.9^{o}

Displacement d= \sqrt{r_x^2 + r_y^2}

                     d = \sqrt{48.9^2+42.4^2} = 64.7 km

d= 64.7 km

displacement vector=r_xi + r_yj =  48.9i + 42.4j

8 0
3 years ago
The graph is the path Beth took on a walk.
PIT_PIT [208]

Answer:

Beth went back toward her origin

Explanation:

Please, see the attached image that represent's Beth's path.

She started her walk 2 meters from the origin (0) and after 6 seconds she headed back to position zero (0) the origin. Notice the second half of the graph as a segment going down, thus reducing her distance from the origin, and getting closer to it.

6 0
3 years ago
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An emergency relief plane is dropping a care package from a plane to a group of medical personnel working for a relief agency in
ipn [44]

Answer:

The altitude of the plane is 379.5 m.

Explanation:

Initial horizontal velocity, u = 59.1 m/s

Horizontal distance, d = 521 m

let the time taken by the packet to cover the distance is t.

Horizontal distance = horizontal velocity x time

521 = 59.1 x t

t = 8.8 s

let the vertical height is h .

Use second equation of motion in vertical direction.

h = u t  + 0.5 gt^2\\\\h = 0 + 4.9 \times 8.8\times8.8\\\\h= 379.5 m

7 0
3 years ago
Una mujer esta segando su prado con segadora eléctrica cuya cuchilla gira a 1500rpm. La mujer encuentra una zona de hierba alta
maks197457 [2]

Answer:

α= 15.4[rad/s^2], 500 [rev/min]

Explanation:

La aceleración angular constante esta definida por la siguiente ecuación:

w=w_{0} + \alpha *t\\Donde:\\w=2000 [\frac{rev}{min}]*[\frac{1min}{60s} ] *[\frac{2\pi rad}{1 rev} ]=209.4[\frac{rad}{s} ]\\w_{0} =1500 [\frac{rev}{min}]*[\frac{1min}{60s} ] *[\frac{2\pi rad}{1 rev} ]=157.1[\frac{rad}{s} ]\\t=3.4[s]\\reemplazando:\\209.4-157.1=\alpha *(3.4)\\\\alpha =15.4[\frac{rad}{s^{2} } ]

Para poder llegar a las 2000 [revoluciones /min] estando en 1500 [rev/min], la cuchilla tuvo que incrementar su numero de revoluciones a 500 [rev/min]. Mientras aceleraba.

3 0
3 years ago
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